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A vertical cut is made in a pure saturated clay having undrained shear strength of 150 kN/m2 (consider smooth vertical back). How much actual height (m) of this vertical cut be made such that there is a 400% factor of safety against shear failure.
Take γsat of clay = 19 kN/m3.
    Correct answer is '7.75-7.95'. Can you explain this answer?
    Verified Answer
    A vertical cut is made in a pure saturated clay having undrained shear...
    Concept:
    Maximum height of vertical cut is given by:
    γ = γsat
    For pure clay ɸ = 0°
    cu = undrained cohesion in clay
    Where,
    τu = undrained shear strength of clay
    Cu = undrained cohesion in clay
    ɸu = undrained friction angle
    Calculation:
    As, ɸu = 0°
    τu = Cu + 0
    150 = Cu
    Hc = 31.58 m
    Ho = Actual height of vertical cut
    Ho = 7.895 m
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    Most Upvoted Answer
    A vertical cut is made in a pure saturated clay having undrained shear...
    - Given data:
    - Undrained shear strength (su) = 150 kN/m2
    - Unit weight of saturated clay (γsat) = 19 kN/m3
    - Factor of safety (FOS) = 400%
    - Calculations:
    - The shear strength of the soil can be calculated as:
    - τ = su = 150 kN/m2
    - The total stress at the base of the cut can be calculated as:
    - σ = γh
    - The total stress at the base of the cut just before failure can be calculated as:
    - σf = FOS * σ = FOS * γh
    - The shear stress at the base of the cut can be calculated as:
    - τ = C + σ tan(φ)
    - For undrained conditions, C = 0
    - Therefore, τ = σ tan(φ)
    - Equating the shear stress to the shear strength:
    - σ tan(φ) = su
    - Substituting the values and solving for h:
    - 19h * tan(φ) = 150
    - h = 150 / (19 * tan(φ))
    - Final step:
    - Since the factor of safety (FOS) is 400%, the actual height (h) of the cut should be such that:
    - h = FOS * calculated height
    - h = 4 * (150 / (19 * tan(φ)))
    - h ≈ 7.75 - 7.95 meters
    Therefore, the actual height of the vertical cut should be between 7.75 to 7.95 meters to ensure a 400% factor of safety against shear failure.
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    A vertical cut is made in a pure saturated clay having undrained shear strength of 150 kN/m2(consider smooth vertical back). How much actual height (m) of this vertical cut be made such that there is a 400% factor of safety against shear failure.Take γsatof clay = 19 kN/m3.Correct answer is '7.75-7.95'. Can you explain this answer?
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    A vertical cut is made in a pure saturated clay having undrained shear strength of 150 kN/m2(consider smooth vertical back). How much actual height (m) of this vertical cut be made such that there is a 400% factor of safety against shear failure.Take γsatof clay = 19 kN/m3.Correct answer is '7.75-7.95'. Can you explain this answer? for Civil Engineering (CE) 2024 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about A vertical cut is made in a pure saturated clay having undrained shear strength of 150 kN/m2(consider smooth vertical back). How much actual height (m) of this vertical cut be made such that there is a 400% factor of safety against shear failure.Take γsatof clay = 19 kN/m3.Correct answer is '7.75-7.95'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A vertical cut is made in a pure saturated clay having undrained shear strength of 150 kN/m2(consider smooth vertical back). How much actual height (m) of this vertical cut be made such that there is a 400% factor of safety against shear failure.Take γsatof clay = 19 kN/m3.Correct answer is '7.75-7.95'. Can you explain this answer?.
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