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How many words can be made out from the letters of the word "INDEPENDENCE" in which vowels always come together?
Most Upvoted Answer
How many words can be made out from the letters of the word "INDEPENDE...
There are 5 vowels I.e. 4 e and 1 i
And 7 consonants I.e. 3n and 2d. 1p. 1c


So see vowels together as one entity we have 8 letters

Now total ways to arrange 7 consonants and that one vowel entity becomes___ (8!)/2!*3! = 3360

Now total ways to arrange vowels____(5!)/4! = 5


Now total words that can be made __3360*5 =16800
That Is the required answer. Hope it helps
Community Answer
How many words can be made out from the letters of the word "INDEPENDE...
Number of Words with Vowels Always Together in "INDEPENDENCE"

To find the number of words that can be made from the letters of the word "INDEPENDENCE" in which vowels always come together, we need to follow these steps:

Step 1: Identify the Vowels

First, let's identify the vowels in the word "INDEPENDENCE." The vowels in this word are I, E, E, and E.

Step 2: Group the Vowels

Next, let's group the vowels together as per the given condition. In this case, we have three E's that need to be together. Therefore, we can consider them as a single unit.

So, we can treat the vowels as one entity, "EEE," and consider it as a single letter while arranging the letters.

Step 3: Find the Number of Arrangements

Now, we have the letters "NNDDPNNC" along with the grouped vowels "EEE." We need to find the number of arrangements possible with these letters.

To calculate the number of arrangements, we'll use the concept of permutations. The formula for permutations is:

n! / (n1! * n2! * n3! * ... * nk!)

Where n is the total number of objects, and n1, n2, n3, ..., nk are the number of repetitions of each object.

In our case, we have 10 letters in total: 3 N's, 2 D's, 2 E's, 1 I, 1 P, and 1 C.

So, the number of arrangements would be:

10! / (3! * 2! * 2! * 1! * 1! * 1!) = 10! / (3! * 2! * 2!)

Step 4: Calculate the Number of Arrangements

Now, let's calculate the number of arrangements using the formula mentioned above:

10! = 10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1 = 3,628,800
3! = 3 * 2 * 1 = 6
2! = 2 * 1 = 2

Therefore, the number of arrangements is:

3,628,800 / (6 * 2 * 2) = 3,628,800 / 24 = 151,200

Step 5: Final Result

So, there are 151,200 words that can be made out of the letters of the word "INDEPENDENCE" in which the vowels always come together.

Summary:

Using the concept of permutations, we determined that there are 151,200 words that can be formed from the letters of the word "INDEPENDENCE," ensuring that the vowels always come together.
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How many words can be made out from the letters of the word "INDEPENDENCE" in which vowels always come together?
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How many words can be made out from the letters of the word "INDEPENDENCE" in which vowels always come together? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about How many words can be made out from the letters of the word "INDEPENDENCE" in which vowels always come together? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How many words can be made out from the letters of the word "INDEPENDENCE" in which vowels always come together?.
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