A racing car moving with constant acceleration covers two succesive ki...
Problem: A racing car moving with constant acceleration covers two successive kilometers in 30 seconds and 20 seconds respectively. Find the acceleration of the car?
Solution:
We have to find the acceleration of a racing car that covers two successive kilometers in 30 seconds and 20 seconds respectively. Let's assume the initial velocity of the car is u, the final velocity is v, and the time taken to cover the first kilometer is t1, and for the second kilometer is t2.
Using the formula,
v = u + at
where, a is the acceleration of the car.
First Kilometer:
Given, distance (s1) = 1 km, time (t1) = 30 s, initial velocity (u) = 0 (as the car was at rest)
Using the formula of motion,
s1 = ut1 + (1/2)at1^2
1 = 0 + (1/2)at1^2
a = (2*1)/(t1^2)
a = 4/900 m/s^2
Second Kilometer:
Given, distance (s2) = 1 km, time (t2) = 20 s, initial velocity (u) = v (as the car was moving after covering the first kilometer)
Using the formula of motion,
s2 = ut2 + (1/2)at2^2
1 = vt2 + (1/2)a(t2^2)
Using the formula, v = u + at
v = v + a(t2)
a = (2*1)/(t2^2)
a = 5/400 m/s^2
Final Acceleration:
The acceleration of the car is the average of the acceleration calculated for the first kilometer and the second kilometer.
a = (4/900 + 5/400)/2
a = 0.07 m/s^2
Therefore, the acceleration of the racing car is 0.07 m/s^2.
A racing car moving with constant acceleration covers two succesive ki...
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