In a catchment there are five rain gauge stations A, B, C, D and E are located on a circular shape basin of diameter 24 km as shown in figure below. If the rainfall at station A, B, C, D and E in the month of August are 250 cm, 200 cm, 225 cm, 240 cm and 210 cm respectively, then the average rainfall (in m, up to two decimal place) over the catchment in month of August will be __________.Correct answer is '0.228-0.23'. Can you explain this answer?

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In a catchment there are five rain gauge stations A, B, C, D and E are located on a circular shape basin of diameter 24 km as shown in figure below. If the rainfall at station A, B, C, D and E in the month of August are 250 cm, 200 cm, 225 cm, 240 cm and 210 cm respectively, then the average rainfall (in m, up to two decimal place) over the catchment in month of August will be __________.

Correct answer is '0.228-0.23'. Can you explain this answer?

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In a catchment there are five rain gauge stations A, B, C, D and E are...

Thiessen Polygon Method:

This method is also known as weighted area method. The rainfall data at every station is given a weightage on the basis of an area close to the station

Where Pavg = Average Precipitation

P1, P2, ........Pn are precipitation at station 1, 2, ....., n respectively

A1, A2, ........An is the area for station 1, 2, ....., n respectively

This method of fining average rainfall is suitable

→ when the area is large

→ rainfall varies from place to place

1) In order to find the representative area, all the stations are joined, so as to form a network, of the non-intersection triangle.

2) Perpendicular bisector is then drawer from the sides of the triangle in such a way that a representative area is obtained for each of the rain gauge stations.

Calculation:

Catchment diameter = 24 km

Catchment area for station A

= (12 × 12) km²

= 144 km²

∴ Total area of catchment

= 452.4 km²

∴ Catchment area for B, C, D, and E will be equal and

= 77.1 km²

∴ Mean Rainfall

Mean Rainfall =228.7 cm = 0.2287 m

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