A traffic survey is conducted on an intersection to compute practical ...
Concept:
Practical capacity of Rotary
Where W = width of weaving section.
e = Average width at entry and exit =

P = proportion of weaving traffic
L = length of the weaving section.
The above expression will be valid only when these four conditions will be satisfied
A. 6m ≤ w ≤ 18m
D. 0.4 ≤ P ≤ 1
Calculation:
Given:
W = 15m
L = 54m
e = 8m
P = 60%
Practical capacity of Rotary
Qp = 3665.5 vehicle/hr
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A traffic survey is conducted on an intersection to compute practical ...
Given Data:
- Width of the weaving section = 12m
- Length of the weaving section = 54m
- Proportion of weaving traffic = 60%
- Average width of entry and exit = 8m
Calculating the Weaving Traffic Volume:
To compute the practical capacity of the intersection, we first need to calculate the weaving traffic volume. We can do this by multiplying the length of the weaving section by the width of the weaving section and the proportion of weaving traffic:
Weaving Traffic Volume = Length of Weaving Section * Width of Weaving Section * Proportion of Weaving Traffic
= 54m * 12m * 0.60
= 388.8 square meters
Calculating the Capacity:
Next, we need to calculate the capacity of the intersection. The capacity represents the maximum number of vehicles that can pass through the intersection per hour. It can be calculated using the formula:
Capacity = (Weaving Traffic Volume / Width of Entry and Exit) * 3600
= (388.8 square meters / 8m) * 3600
= 194400 vehicles/hr
Range of Practical Capacity:
The practical capacity of the intersection can vary depending on various factors such as signal timings, driver behavior, and road conditions. The range of practical capacity is typically given to account for these variations. In this case, the practical capacity is given as 3660-3770 vehicles/hr.
Therefore, the correct answer is '3660-3770' vehicles/hr.