Copper sulphate, also known as cupric sulphate or blue vitriol, is a chemical compound with the formula CuSO4. It is commonly encountered as a hydrated salt with five molecules of water (CuSO4 · 5H2O). Copper sulphate has several important properties and reactions, and it is used in various applications such as in agriculture, electroplating, and as a laboratory reagent.

Let's analyze each option to determine which one is not correct regarding copper sulphate:

a) It reacts with NaOH and glucose to give Cu2O:
Copper sulphate does not react with NaOH and glucose to give Cu2O. The reaction of copper sulphate with sodium hydroxide (NaOH) results in the formation of a blue precipitate of copper hydroxide (Cu(OH)2). The reaction can be represented by the following equation:
CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4

b) It reacts with KCI to give Cu2CI2:
This statement is incorrect. Copper sulphate does not react with potassium chloride (KCl) to give Cu2Cl2. Copper sulphate is a salt that contains copper in the +2 oxidation state, while Cu2Cl2 is a compound in which copper is in the +1 oxidation state. Therefore, there is no reaction between copper sulphate and potassium chloride.

c) It gives CuO on strong heating in air:
This statement is correct. Copper sulphate decomposes on strong heating in air to give copper(II) oxide (CuO) and sulphur trioxide (SO3). The reaction can be represented by the following equation:
2CuSO4 → 2CuO + 2SO2 + O2

d) It reacts with KI to give iodine:
This statement is correct. Copper sulphate reacts with potassium iodide (KI) to give copper(I) iodide (CuI) and iodine (I2). The reaction can be represented by the following equation:
2CuSO4 + 4KI → 2CuI + I2 + 2K2SO4

In conclusion, the correct answer is option 'B' because copper sulphate does not react with potassium chloride to give copper(II) chloride (Cu2Cl2).