Class 12 Exam > Class 12 Questions > An ester is boiled with KOH. The product isco...
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An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]
- a)Methyl acetate
- b)Ethyl acetate
- c)Ethyl formate
- d)Ethyl benzoate
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
An ester is boiled with KOH. The product iscooled and acidified with c...
Methyl acetate and ethyl acetate on
hydrolysis give CH3COOH which is a liquid. Similarly ethyl formate on hydrolysis will give formic acid which is also a liquid. Only ethyl benzoate on hydrolysis will give benzoic acid
which is a solid.
hydrolysis give CH3COOH which is a liquid. Similarly ethyl formate on hydrolysis will give formic acid which is also a liquid. Only ethyl benzoate on hydrolysis will give benzoic acid
which is a solid.
Most Upvoted Answer
An ester is boiled with KOH. The product iscooled and acidified with c...
Lets analyse the given option for the correct answer,
1. Methyl actetate on hydrolysis gives acetic acid in liquid state
2. Ethyl acetate on hydrolysis gives acetic acid in liquid state
3. Ethyl formate on hydrolysis gives formic acid in liquid state
4. Ethyl benzoate on hydrolysis gives benzoic acid in solid state
So it clear white crystalline product forms from ethyl benzoate, hence the answer is Option (D) Ethyl Benzoate.
1. Methyl actetate on hydrolysis gives acetic acid in liquid state
2. Ethyl acetate on hydrolysis gives acetic acid in liquid state
3. Ethyl formate on hydrolysis gives formic acid in liquid state
4. Ethyl benzoate on hydrolysis gives benzoic acid in solid state
So it clear white crystalline product forms from ethyl benzoate, hence the answer is Option (D) Ethyl Benzoate.
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An ester is boiled with KOH. The product iscooled and acidified with c...
The given question is related to the reaction of an ester with KOH and subsequent acidification with HCl. The product obtained after acidification is a white crystalline acid. We need to identify the ester that is used in this reaction.
Ester Hydrolysis Reaction:
- The reaction of an ester with a strong base, such as KOH, is known as ester hydrolysis.
- In this reaction, the ester undergoes cleavage to form an alcohol and a carboxylate ion.
- The carboxylate ion then reacts with the base to form the salt of the carboxylic acid.
Acidification Reaction:
- After the ester hydrolysis reaction, the product is cooled and then acidified with concentrated HCl.
- Acidification converts the carboxylate salt back into the corresponding carboxylic acid.
- The carboxylic acid obtained from this reaction is a white crystalline acid.
Identifying the Ester:
- To determine the ester used in the reaction, we need to consider the product obtained after acidification.
- The fact that the product is a white crystalline acid indicates that the ester used is likely to have a carboxylic acid functional group.
- Among the given options, only "D) Ethyl benzoate" contains a benzoic acid functional group.
- Therefore, the correct answer is option D) Ethyl benzoate.
In summary, when an ester is boiled with KOH, it undergoes hydrolysis to form an alcohol and a carboxylate ion. The carboxylate ion reacts with KOH to form the salt of the carboxylic acid. Upon acidification with concentrated HCl, the carboxylate salt is converted back into the carboxylic acid, which is a white crystalline acid. Based on this information, the ester used in the reaction is identified as Ethyl benzoate (option D).
Ester Hydrolysis Reaction:
- The reaction of an ester with a strong base, such as KOH, is known as ester hydrolysis.
- In this reaction, the ester undergoes cleavage to form an alcohol and a carboxylate ion.
- The carboxylate ion then reacts with the base to form the salt of the carboxylic acid.
Acidification Reaction:
- After the ester hydrolysis reaction, the product is cooled and then acidified with concentrated HCl.
- Acidification converts the carboxylate salt back into the corresponding carboxylic acid.
- The carboxylic acid obtained from this reaction is a white crystalline acid.
Identifying the Ester:
- To determine the ester used in the reaction, we need to consider the product obtained after acidification.
- The fact that the product is a white crystalline acid indicates that the ester used is likely to have a carboxylic acid functional group.
- Among the given options, only "D) Ethyl benzoate" contains a benzoic acid functional group.
- Therefore, the correct answer is option D) Ethyl benzoate.
In summary, when an ester is boiled with KOH, it undergoes hydrolysis to form an alcohol and a carboxylate ion. The carboxylate ion reacts with KOH to form the salt of the carboxylic acid. Upon acidification with concentrated HCl, the carboxylate salt is converted back into the carboxylic acid, which is a white crystalline acid. Based on this information, the ester used in the reaction is identified as Ethyl benzoate (option D).
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An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]a)Methyl acetateb)Ethyl acetatec)Ethyl formated)Ethyl benzoateCorrect answer is option 'D'. Can you explain this answer?
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An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]a)Methyl acetateb)Ethyl acetatec)Ethyl formated)Ethyl benzoateCorrect answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]a)Methyl acetateb)Ethyl acetatec)Ethyl formated)Ethyl benzoateCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]a)Methyl acetateb)Ethyl acetatec)Ethyl formated)Ethyl benzoateCorrect answer is option 'D'. Can you explain this answer?.
An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]a)Methyl acetateb)Ethyl acetatec)Ethyl formated)Ethyl benzoateCorrect answer is option 'D'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]a)Methyl acetateb)Ethyl acetatec)Ethyl formated)Ethyl benzoateCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]a)Methyl acetateb)Ethyl acetatec)Ethyl formated)Ethyl benzoateCorrect answer is option 'D'. Can you explain this answer?.
Solutions for An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]a)Methyl acetateb)Ethyl acetatec)Ethyl formated)Ethyl benzoateCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
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An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]a)Methyl acetateb)Ethyl acetatec)Ethyl formated)Ethyl benzoateCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]a)Methyl acetateb)Ethyl acetatec)Ethyl formated)Ethyl benzoateCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of An ester is boiled with KOH. The product iscooled and acidified with concentrated HCl. Awhite crystalline acid separates. The ester is[1994]a)Methyl acetateb)Ethyl acetatec)Ethyl formated)Ethyl benzoateCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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