Which one of the following is an outer orbital complex and exhibits pa...
[Ni(NH3)6]2+
Ni
2+ = 3d
8, according to
therefore, hybridisation is sp
3d
2 & complex is paramagnetic.
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Which one of the following is an outer orbital complex and exhibits pa...
[Ni(NH3)6]2+ : sp3d2 (outer), octahedral, paramagnetic [Zn(NH3)6]2+ : sp3d2 (outer), octahedral, diamagnetic [Cr(NH3)6]3+ : d2sp3 (inner), octahedral, paramagnetic [Co(NH3)6]3+ : d2sp3 (inner). octahedral,
Which one of the following is an outer orbital complex and exhibits pa...
Outer orbital complexes are those in which the metal ion utilizes its outer d orbitals for bonding. These complexes typically have a high spin configuration and exhibit paramagnetic behavior.
Let's analyze each option to determine which one fits the criteria:
a) [Ni(NH3)6]2:
- Nickel (Ni) is a transition metal with the electron configuration [Ar]3d84s2.
- In this complex, nickel is in the +2 oxidation state.
- The coordination number of nickel is 6, indicating that it forms a complex with six ammonia (NH3) ligands.
- Since nickel has four outer d electrons available, it can utilize these orbitals for bonding with the ligands.
- The complex has a high spin configuration as it maximizes the number of unpaired electrons.
- Therefore, [Ni(NH3)6]2 is an outer orbital complex and exhibits paramagnetic behavior.
b) [Zn(NH3)6]2:
- Zinc (Zn) is also a transition metal with the electron configuration [Ar]3d104s2.
- In this complex, zinc is in the +2 oxidation state.
- The coordination number of zinc is 6, indicating that it forms a complex with six ammonia (NH3) ligands.
- However, zinc has completely filled d orbitals and does not have any outer d electrons available for bonding.
- The complex has a low spin configuration with all electrons paired.
- Therefore, [Zn(NH3)6]2 is not an outer orbital complex and does not exhibit paramagnetic behavior.
c) [Cr(NH3)6]3:
- Chromium (Cr) is a transition metal with the electron configuration [Ar]3d54s1.
- In this complex, chromium is in the +3 oxidation state.
- The coordination number of chromium is 6, indicating that it forms a complex with six ammonia (NH3) ligands.
- Chromium has three outer d electrons available for bonding with the ligands.
- However, in this case, the complex has a low spin configuration as it maximizes the pairing of electrons.
- Therefore, [Cr(NH3)6]3 is not an outer orbital complex and does not exhibit paramagnetic behavior.
d) [CO(NH3)6]3:
- Carbon monoxide (CO) is not a ligand that typically forms outer orbital complexes.
- Therefore, [CO(NH3)6]3 is not an outer orbital complex and does not exhibit paramagnetic behavior.
In conclusion, the correct answer is option a) [Ni(NH3)6]2, which is an outer orbital complex and exhibits paramagnetic behavior.