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The flux linked with a coil at any instant 't' is given by φ = 10t2 - 50t + 250 . The induced emf at t = 3s is
- a)–190 V
- b)10 V
- c)- 10 V
- d)190 V
Correct answer is option 'C'. Can you explain this answer?
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The flux linked with a coil at any instant t is given by φ = 10t2 ...
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The flux linked with a coil at any instant t is given by φ = 10t2 ...
The flux linked with a coil at any instant t is given by the equation:
Φ = N * B * A * cos(ωt + φ)
Where:
Φ is the flux linked with the coil
N is the number of turns in the coil
B is the magnetic field strength
A is the area of the coil
ω is the angular frequency of the magnetic field
t is the time
φ is the phase angle between the magnetic field and the coil
This equation represents the change in magnetic flux through the coil over time and is commonly used in electromagnetic induction and Faraday's law of induction.
Φ = N * B * A * cos(ωt + φ)
Where:
Φ is the flux linked with the coil
N is the number of turns in the coil
B is the magnetic field strength
A is the area of the coil
ω is the angular frequency of the magnetic field
t is the time
φ is the phase angle between the magnetic field and the coil
This equation represents the change in magnetic flux through the coil over time and is commonly used in electromagnetic induction and Faraday's law of induction.
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The flux linked with a coil at any instant t is given by φ = 10t2 - 50t + 250 . The induced emf at t = 3s isa)–190 Vb)10 Vc)- 10 Vd)190 VCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The flux linked with a coil at any instant t is given by φ = 10t2 - 50t + 250 . The induced emf at t = 3s isa)–190 Vb)10 Vc)- 10 Vd)190 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The flux linked with a coil at any instant t is given by φ = 10t2 - 50t + 250 . The induced emf at t = 3s isa)–190 Vb)10 Vc)- 10 Vd)190 VCorrect answer is option 'C'. Can you explain this answer?.
The flux linked with a coil at any instant t is given by φ = 10t2 - 50t + 250 . The induced emf at t = 3s isa)–190 Vb)10 Vc)- 10 Vd)190 VCorrect answer is option 'C'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The flux linked with a coil at any instant t is given by φ = 10t2 - 50t + 250 . The induced emf at t = 3s isa)–190 Vb)10 Vc)- 10 Vd)190 VCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The flux linked with a coil at any instant t is given by φ = 10t2 - 50t + 250 . The induced emf at t = 3s isa)–190 Vb)10 Vc)- 10 Vd)190 VCorrect answer is option 'C'. Can you explain this answer?.
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