An electron in a one dimensional box of width 1A• undergoes a transiti...
Calculating the Transition Energy
To calculate the transition energy, we need to use the formula:
E = (n^2 * h^2) / (8*m*L^2)
where E is the energy of the state, n is the quantum number of the state (n=1 for the ground state and n=2 for the first excited state), h is Planck's constant, m is the mass of the electron, and L is the width of the box.
Substituting the Values
Substituting the given values, we get:
For the ground state (n=1):
E1 = (1^2 * h^2) / (8*m*L^2)
E1 = (1 * 6.626 x 10^-34 J s)^2 / (8 * 9.109 x 10^-31 kg * (1 x 10^-10 m)^2)
E1 = 3.38 x 10^-18 J
For the first excited state (n=2):
E2 = (2^2 * h^2) / (8*m*L^2)
E2 = (4 * 6.626 x 10^-34 J s)^2 / (8 * 9.109 x 10^-31 kg * (1 x 10^-10 m)^2)
E2 = 1.35 x 10^-17 J
Converting Joules to Electron Volts
To convert the energy from Joules to electron volts (eV), we need to divide the energy by the elementary charge (e):
1 eV = 1.602 x 10^-19 J
Therefore, the transition energy is:
E2 - E1 = (1.35 x 10^-17 J) - (3.38 x 10^-18 J)
E2 - E1 = 9.72 x 10^-18 J
E2 - E1 = 60.6 eV (approx.)
Thus, the transition energy from the ground state to the first excited state is approximately 60.6 eV.