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A small body of mass 0.2 kg undergoes a uniform circular motion on a frictionless horizontal surface. The body is attached to the centre by a string of length 2m and has a linear speed of 10 m/s. The force exerted by the string on the mass is _________ N
Correct answer is '10'. Can you explain this answer?
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A small body of mass 0.2 kg undergoes a uniform circular motion on a f...
Given speed v = 10 m/s
Required centripetal force provided by tension in the string, to move in circle with constant speed,
T = mv2/r
Required centripetal force provided by tension in the string, to move in circle with constant speed,
T = mv2/r
Most Upvoted Answer
A small body of mass 0.2 kg undergoes a uniform circular motion on a f...
Given information:
- Mass of the body (m) = 0.2 kg
- Length of the string (r) = 2 m
- Linear speed of the body (v) = 10 m/s
Concepts to be used:
- Centripetal force (Fc) = (m * v^2) / r
- Centripetal force is provided by the tension in the string
Solution:
To find the force exerted by the string on the mass, we need to calculate the centripetal force acting on the mass.
Step 1: Calculate the centripetal force using the given formula:
Fc = (m * v^2) / r
Step 2: Substitute the given values into the formula:
Fc = (0.2 kg * (10 m/s)^2) / 2 m
Step 3: Simplify the equation:
Fc = (0.2 kg * 100 m^2/s^2) / 2 m
Fc = (20 kg m^2/s^2) / 2 m
Fc = 10 N
Therefore, the force exerted by the string on the mass is 10 N.
- Mass of the body (m) = 0.2 kg
- Length of the string (r) = 2 m
- Linear speed of the body (v) = 10 m/s
Concepts to be used:
- Centripetal force (Fc) = (m * v^2) / r
- Centripetal force is provided by the tension in the string
Solution:
To find the force exerted by the string on the mass, we need to calculate the centripetal force acting on the mass.
Step 1: Calculate the centripetal force using the given formula:
Fc = (m * v^2) / r
Step 2: Substitute the given values into the formula:
Fc = (0.2 kg * (10 m/s)^2) / 2 m
Step 3: Simplify the equation:
Fc = (0.2 kg * 100 m^2/s^2) / 2 m
Fc = (20 kg m^2/s^2) / 2 m
Fc = 10 N
Therefore, the force exerted by the string on the mass is 10 N.
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A small body of mass 0.2 kg undergoes a uniform circular motion on a frictionless horizontal surface. The body is attached to the centre by a string of length 2m and has a linear speed of 10 m/s. The force exerted by the string on the mass is _________ NCorrect answer is '10'. Can you explain this answer?
Question Description
A small body of mass 0.2 kg undergoes a uniform circular motion on a frictionless horizontal surface. The body is attached to the centre by a string of length 2m and has a linear speed of 10 m/s. The force exerted by the string on the mass is _________ NCorrect answer is '10'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A small body of mass 0.2 kg undergoes a uniform circular motion on a frictionless horizontal surface. The body is attached to the centre by a string of length 2m and has a linear speed of 10 m/s. The force exerted by the string on the mass is _________ NCorrect answer is '10'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A small body of mass 0.2 kg undergoes a uniform circular motion on a frictionless horizontal surface. The body is attached to the centre by a string of length 2m and has a linear speed of 10 m/s. The force exerted by the string on the mass is _________ NCorrect answer is '10'. Can you explain this answer?.
A small body of mass 0.2 kg undergoes a uniform circular motion on a frictionless horizontal surface. The body is attached to the centre by a string of length 2m and has a linear speed of 10 m/s. The force exerted by the string on the mass is _________ NCorrect answer is '10'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A small body of mass 0.2 kg undergoes a uniform circular motion on a frictionless horizontal surface. The body is attached to the centre by a string of length 2m and has a linear speed of 10 m/s. The force exerted by the string on the mass is _________ NCorrect answer is '10'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A small body of mass 0.2 kg undergoes a uniform circular motion on a frictionless horizontal surface. The body is attached to the centre by a string of length 2m and has a linear speed of 10 m/s. The force exerted by the string on the mass is _________ NCorrect answer is '10'. Can you explain this answer?.
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