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A uniform circular disc of mass 200 g and radius 4 cm is rotated about one of its diameter at an angular speed of 10 rad/s. The ratio of its kinetic energy to its angular momentum about the axis of rotation is
  • a)
    5
  • b)
    10
  • c)
    1
  • d)
    20
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
A uniform circular disc of mass 200 g and radius 4 cm is rotated about...
The moment of inertia of the circular disc about is diametter is

and the angular momentum about the axis of rotation is
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Most Upvoted Answer
A uniform circular disc of mass 200 g and radius 4 cm is rotated about...
Given data:
Mass of the disc (m) = 200 g = 0.2 kg
Radius of the disc (r) = 4 cm = 0.04 m
Angular speed of rotation (ω) = 10 rad/s

We need to find the ratio of the kinetic energy (KE) to the angular momentum (L) about the axis of rotation.

1. Calculating the moment of inertia (I) of the disc:
The moment of inertia of a uniform circular disc rotating about an axis perpendicular to its plane and passing through its center is given by the formula:
I = (1/4) * m * r^2

Substituting the given values:
I = (1/4) * 0.2 kg * (0.04 m)^2
I = 0.0016 kg·m^2

2. Calculating the kinetic energy (KE) of the disc:
The kinetic energy of a rotating object is given by the formula:
KE = (1/2) * I * ω^2

Substituting the given values:
KE = (1/2) * 0.0016 kg·m^2 * (10 rad/s)^2
KE = 0.08 J

3. Calculating the angular momentum (L) of the disc:
The angular momentum of a rotating object is given by the formula:
L = I * ω

Substituting the given values:
L = 0.0016 kg·m^2 * 10 rad/s
L = 0.016 kg·m^2/s

4. Calculating the ratio of kinetic energy to angular momentum:
Ratio = KE / L
Ratio = 0.08 J / 0.016 kg·m^2/s
Ratio = 5 J·s/J·s
Ratio = 5

Hence, the ratio of the kinetic energy to the angular momentum about the axis of rotation is 5, which corresponds to option A.
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A uniform circular disc of mass 200 g and radius 4 cm is rotated about one of its diameter at an angular speed of 10 rad/s. The ratio of its kinetic energy to its angular momentum about the axis of rotation isa)5b)10c)1d)20Correct answer is option 'A'. Can you explain this answer?
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