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A 0.10 cm diameter and 15 cm long wire has been laid horizontally and submerged in water at atmospheric pressure. The wire has a steady state voltage drop of 14.5 V and a current of 42.5 A. Determine the heat flux of the wire.
The following equation applies for water boiling on a horizontal submerged surface
H = 1.54 (Q/A) 0.75 = 5.58 (d t) 3 W/m2 K where Q/A is the heat flux rate in W/m2 and d t is the temperature difference between surface and saturation
The following equation applies for water boiling on a horizontal submerged surface
H = 1.54 (Q/A) 0.75 = 5.58 (d t) 3 W/m2 K where Q/A is the heat flux rate in W/m2 and d t is the temperature difference between surface and saturation
- a)1.308 * 10 8 W/m2
- b)1.308 * 10 7 W/m2
- c)1.308 * 10 6 W/m2
- d)1.308 * 10 5 W/m2
Correct answer is option 'C'. Can you explain this answer?
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A 0.10 cm diameter and 15 cm long wire has been laid horizontally and ...
Q = E I = 616.25 W and A = 4.71 * 10 -4 m2.
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A 0.10 cm diameter and 15 cm long wire has been laid horizontally and ...
Calculation of Heat Flux of the Wire Submerged in Water
Given data:
- Diameter of wire = 0.10 cm
- Length of wire = 15 cm
- Voltage drop across wire = 14.5 V
- Current through wire = 42.5 A
Formula to calculate power dissipated by the wire:
- Power (P) = V x I
- P = 14.5 V x 42.5 A
- P = 616.25 W
Formula to calculate surface area of the wire:
- Surface area (A) = π x (d/2)^2 x L
- A = π x (0.10/2)^2 x 15
- A = 0.01178 m^2
Formula to calculate heat flux rate:
- Q/A = P/A
- Q/A = 616.25 W/0.01178 m^2
- Q/A = 52,290.61 W/m^2
Formula to calculate temperature difference between wire surface and saturation:
- d t = (P/H x A)^0.25
- d t = (52,290.61/5.58)^0.75
- d t = 38.78 K
Formula to calculate heat flux:
- H = 5.58 x (d t)^3
- H = 5.58 x (38.78)^3
- H = 1.308 x 10^6 W/m^2
Therefore, the heat flux of the wire submerged in water is 1.308 x 10^6 W/m^2, which is option C.
Given data:
- Diameter of wire = 0.10 cm
- Length of wire = 15 cm
- Voltage drop across wire = 14.5 V
- Current through wire = 42.5 A
Formula to calculate power dissipated by the wire:
- Power (P) = V x I
- P = 14.5 V x 42.5 A
- P = 616.25 W
Formula to calculate surface area of the wire:
- Surface area (A) = π x (d/2)^2 x L
- A = π x (0.10/2)^2 x 15
- A = 0.01178 m^2
Formula to calculate heat flux rate:
- Q/A = P/A
- Q/A = 616.25 W/0.01178 m^2
- Q/A = 52,290.61 W/m^2
Formula to calculate temperature difference between wire surface and saturation:
- d t = (P/H x A)^0.25
- d t = (52,290.61/5.58)^0.75
- d t = 38.78 K
Formula to calculate heat flux:
- H = 5.58 x (d t)^3
- H = 5.58 x (38.78)^3
- H = 1.308 x 10^6 W/m^2
Therefore, the heat flux of the wire submerged in water is 1.308 x 10^6 W/m^2, which is option C.
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A 0.10 cm diameter and 15 cm long wire has been laid horizontally and submerged in water at atmospheric pressure. The wire has a steady state voltage drop of 14.5 V and a current of 42.5 A. Determine the heat flux of the wire.The following equation applies for water boiling on a horizontal submerged surfaceH = 1.54 (Q/A)0.75= 5.58 (d t)3W/m2K where Q/A is the heat flux rate in W/m2and d t is the temperature difference between surface and saturationa)1.308 * 108W/m2b)1.308 * 107W/m2c)1.308 * 106W/m2d)1.308 * 105W/m2Correct answer is option 'C'. Can you explain this answer?
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A 0.10 cm diameter and 15 cm long wire has been laid horizontally and submerged in water at atmospheric pressure. The wire has a steady state voltage drop of 14.5 V and a current of 42.5 A. Determine the heat flux of the wire.The following equation applies for water boiling on a horizontal submerged surfaceH = 1.54 (Q/A)0.75= 5.58 (d t)3W/m2K where Q/A is the heat flux rate in W/m2and d t is the temperature difference between surface and saturationa)1.308 * 108W/m2b)1.308 * 107W/m2c)1.308 * 106W/m2d)1.308 * 105W/m2Correct answer is option 'C'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A 0.10 cm diameter and 15 cm long wire has been laid horizontally and submerged in water at atmospheric pressure. The wire has a steady state voltage drop of 14.5 V and a current of 42.5 A. Determine the heat flux of the wire.The following equation applies for water boiling on a horizontal submerged surfaceH = 1.54 (Q/A)0.75= 5.58 (d t)3W/m2K where Q/A is the heat flux rate in W/m2and d t is the temperature difference between surface and saturationa)1.308 * 108W/m2b)1.308 * 107W/m2c)1.308 * 106W/m2d)1.308 * 105W/m2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 0.10 cm diameter and 15 cm long wire has been laid horizontally and submerged in water at atmospheric pressure. The wire has a steady state voltage drop of 14.5 V and a current of 42.5 A. Determine the heat flux of the wire.The following equation applies for water boiling on a horizontal submerged surfaceH = 1.54 (Q/A)0.75= 5.58 (d t)3W/m2K where Q/A is the heat flux rate in W/m2and d t is the temperature difference between surface and saturationa)1.308 * 108W/m2b)1.308 * 107W/m2c)1.308 * 106W/m2d)1.308 * 105W/m2Correct answer is option 'C'. Can you explain this answer?.
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A 0.10 cm diameter and 15 cm long wire has been laid horizontally and submerged in water at atmospheric pressure. The wire has a steady state voltage drop of 14.5 V and a current of 42.5 A. Determine the heat flux of the wire.The following equation applies for water boiling on a horizontal submerged surfaceH = 1.54 (Q/A)0.75= 5.58 (d t)3W/m2K where Q/A is the heat flux rate in W/m2and d t is the temperature difference between surface and saturationa)1.308 * 108W/m2b)1.308 * 107W/m2c)1.308 * 106W/m2d)1.308 * 105W/m2Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A 0.10 cm diameter and 15 cm long wire has been laid horizontally and submerged in water at atmospheric pressure. The wire has a steady state voltage drop of 14.5 V and a current of 42.5 A. Determine the heat flux of the wire.The following equation applies for water boiling on a horizontal submerged surfaceH = 1.54 (Q/A)0.75= 5.58 (d t)3W/m2K where Q/A is the heat flux rate in W/m2and d t is the temperature difference between surface and saturationa)1.308 * 108W/m2b)1.308 * 107W/m2c)1.308 * 106W/m2d)1.308 * 105W/m2Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A 0.10 cm diameter and 15 cm long wire has been laid horizontally and submerged in water at atmospheric pressure. The wire has a steady state voltage drop of 14.5 V and a current of 42.5 A. Determine the heat flux of the wire.The following equation applies for water boiling on a horizontal submerged surfaceH = 1.54 (Q/A)0.75= 5.58 (d t)3W/m2K where Q/A is the heat flux rate in W/m2and d t is the temperature difference between surface and saturationa)1.308 * 108W/m2b)1.308 * 107W/m2c)1.308 * 106W/m2d)1.308 * 105W/m2Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A 0.10 cm diameter and 15 cm long wire has been laid horizontally and submerged in water at atmospheric pressure. The wire has a steady state voltage drop of 14.5 V and a current of 42.5 A. Determine the heat flux of the wire.The following equation applies for water boiling on a horizontal submerged surfaceH = 1.54 (Q/A)0.75= 5.58 (d t)3W/m2K where Q/A is the heat flux rate in W/m2and d t is the temperature difference between surface and saturationa)1.308 * 108W/m2b)1.308 * 107W/m2c)1.308 * 106W/m2d)1.308 * 105W/m2Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Chemical Engineering tests.
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