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Milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. The milk-man has by mistake added water so that he has 8 liters of milk which is half water and half milk. What must he add to make the proportions of the mixture correct?
  • a)
    1 liter milk
  • b)
    1 liter water
  • c)
    2 liters milk
  • d)
    1.5 liter milk
  • e)
    3 Liter milk
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. ...
We note that the final ratio must be 3:2 for milk and water respectively. Now, according to given scenario in the question, we have eight liters of solution with 4 liters milk and 4 liters water, which makes it 2:2. In order to make it 3:2, we add 2 liters milk. This would make a total of 6 liters milk and 4 liters water i.e. 6:4 which can be simplified to 3:2.
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Most Upvoted Answer
Milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. ...
Given Information:

- The milk-man has 8 liters of milk, which is half water and half milk.
- Milk needs to be thinned to a ratio of 3 parts milk to 2 parts water.

To find:

- What must he add to make the proportions of the mixture correct?

Solution:

Let's assume the milk-man added x liters of water by mistake.

As per the given information, the 8 liters of milk is half water and half milk. So,

- The amount of milk in 8 liters of milk = 1/2 * 8 = 4 liters
- The amount of water in 8 liters of milk = 1/2 * 8 = 4 liters

Now, the milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. So, for every 3 parts of milk, there should be 2 parts of water. Mathematically,

- 3 parts milk = 3/5 * (4 + x) liters
- 2 parts water = 2/5 * (4 + x) liters

Since the milk-man has added x liters of water by mistake, the current ratio of milk to water is:

- Milk = 4 liters
- Water = 4 + x liters

To make the ratio of milk to water 3:2, we need to add more milk. Let's say the milk-man adds y liters of milk to the mixture.

So, the new ratio of milk to water will be:

- Milk = 4 + y liters
- Water = 4 + x liters

As per the given information, the milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. So, we can write the equation:

- (4 + y)/(4 + x) = 3/2

Solving the above equation for y, we get:

- y = 2/3 * x + 2

Now, we need to find the value of y such that the ratio of milk to water becomes 3:2. Let's substitute the value of y in the equation (4 + y)/(4 + x) = 3/2.

- (4 + 2/3 * x + 2)/(4 + x) = 3/2
- 10 + 2/3 * x = 6 + 3/2 * x
- 4 + 1/3 * x = 0
- x = -12

The value of x is negative, which means the milk-man has added 12 liters of milk instead of water. So, the current ratio of milk to water is:

- Milk = 4 + 12 = 16 liters
- Water = 4 - 12 = -8 liters

To make the ratio of milk to water 3:2, we need to add 8 liters of water. But since we cannot add negative water, we need to add more milk. Let's say the milk-man adds z liters of milk to the mixture.

So, the new ratio of milk to water will be:

- Milk = 16 + z liters
- Water = 4 - 12 + 8 = 0 liters

As per the given information, the milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. So, we can
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Milk needs to be thinned to a ratio of 3 parts milk to 2 parts water. The milk-man has by mistake added water so that he has 8 liters of milk which is half water and half milk. What must he add to make the proportions of the mixture correct?a)1 liter milkb)1 liter waterc)2 liters milkd)1.5 liter milke)3 Liter milkCorrect answer is option 'C'. Can you explain this answer?
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