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A class of first year B. Tech. Students is composed of four batches A, B, C and D, each consisting of 30 students. It is found that the sessional marks of students in Engineering Drawing in batch C have a mean of 6.6 and standard deviation of 2.3. The mean and standard deviation of the marks for the entire class are 5.5 and 4.2, respectively. It is decided by the course instructor to normalize the marks of the students of all batches to have the same mean and standard deviation as that of the entire class. Due to this, the marks of a student in batch C are changed from 8.5 to
  • a)
    6.0      
  • b)
    7.0            
  • c)
    8. 0      
  • d)
    9.0 
Correct answer is option 'D'. Can you explain this answer?
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A class of first year B. Tech. Students is composed of four batches A,...
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Option (d)
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A class of first year B. Tech. Students is composed of four batches A,...
Given Information:
- A class of first-year B. Tech. students is composed of four batches A, B, C, and D, each consisting of 30 students.
- The sessional marks of students in Engineering Drawing in batch C have a mean of 6.6 and a standard deviation of 2.3.
- The mean and standard deviation of the marks for the entire class are 5.5 and 4.2, respectively.

Objective:
To determine the new marks of a student in batch C after normalizing the marks of all batches to have the same mean and standard deviation as that of the entire class.

Solution:
To normalize the marks of all batches to have the same mean and standard deviation as that of the entire class, we need to use the formula for standardization:

Z = (X - μ) / σ

Where:
Z = standardized score
X = original score
μ = mean of the distribution
σ = standard deviation of the distribution

Step 1: Calculate the Z-score for the original marks of the student in batch C.
Z = (X - μ) / σ
Z = (8.5 - 6.6) / 2.3
Z ≈ 0.826

Step 2: Calculate the new score using the Z-score formula with the mean and standard deviation of the entire class.
Z = (X - μ) / σ
0.826 = (X - 5.5) / 4.2

Step 3: Solve for X to find the new score.
0.826 * 4.2 = X - 5.5
3.4652 = X - 5.5
X = 3.4652 + 5.5
X ≈ 8.9652

Therefore, the new marks of the student in batch C after normalizing the marks of all batches to have the same mean and standard deviation as that of the entire class is approximately 8.9652, which can be rounded off to 9.0 (option D).
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A class of first year B. Tech. Students is composed of four batches A, B, C and D, each consisting of 30 students. It is found that the sessional marks of students in Engineering Drawing in batch C have a mean of 6.6 and standard deviation of 2.3. The mean and standard deviation of the marks for the entire class are 5.5 and 4.2, respectively. It is decided by the course instructor to normalize the marks of the students of all batches to have the same mean and standard deviation as that of the entire class. Due to this, the marks of a student in batch C are changed from 8.5 toa)6.0 b)7.0 c)8. 0 d)9.0Correct answer is option 'D'. Can you explain this answer?
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A class of first year B. Tech. Students is composed of four batches A, B, C and D, each consisting of 30 students. It is found that the sessional marks of students in Engineering Drawing in batch C have a mean of 6.6 and standard deviation of 2.3. The mean and standard deviation of the marks for the entire class are 5.5 and 4.2, respectively. It is decided by the course instructor to normalize the marks of the students of all batches to have the same mean and standard deviation as that of the entire class. Due to this, the marks of a student in batch C are changed from 8.5 toa)6.0 b)7.0 c)8. 0 d)9.0Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about A class of first year B. Tech. Students is composed of four batches A, B, C and D, each consisting of 30 students. It is found that the sessional marks of students in Engineering Drawing in batch C have a mean of 6.6 and standard deviation of 2.3. The mean and standard deviation of the marks for the entire class are 5.5 and 4.2, respectively. It is decided by the course instructor to normalize the marks of the students of all batches to have the same mean and standard deviation as that of the entire class. Due to this, the marks of a student in batch C are changed from 8.5 toa)6.0 b)7.0 c)8. 0 d)9.0Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A class of first year B. Tech. Students is composed of four batches A, B, C and D, each consisting of 30 students. It is found that the sessional marks of students in Engineering Drawing in batch C have a mean of 6.6 and standard deviation of 2.3. The mean and standard deviation of the marks for the entire class are 5.5 and 4.2, respectively. It is decided by the course instructor to normalize the marks of the students of all batches to have the same mean and standard deviation as that of the entire class. Due to this, the marks of a student in batch C are changed from 8.5 toa)6.0 b)7.0 c)8. 0 d)9.0Correct answer is option 'D'. Can you explain this answer?.
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