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A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal in water at atmospheric pressure. At burnout, the wire has a current of 195 A. Calculate the voltage at burnout. The relevant thermos-physical properties are
p f (fluid) = 959.52 kg/m3
p g (vapor) = 0.597 kg/m3
h f g = 2257000 J/kg
σ = 0.0533 N/m
p f (fluid) = 959.52 kg/m3
p g (vapor) = 0.597 kg/m3
h f g = 2257000 J/kg
σ = 0.0533 N/m
- a)6.15 V
- b)7.15 V
- c)8.15 V
- d)9.15 V
Correct answer is option 'B'. Can you explain this answer?
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A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal ...
(Q/A) MAX = 1480000 W/m2. Let E b be the voltage at burnout. Then electric energy input to wire is E b I = 195 E b W.
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A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal ...
We can use the equation for power in an electrical circuit:
P = VI
where P is power, V is voltage, and I is current. At burnout, the power being dissipated in the wire is equal to the power being supplied by the electrical source, which we can assume to be constant. Thus:
P = VI = constant
We can rearrange this equation to solve for V:
V = P/I
To find the power being dissipated in the wire, we can use the equation for power in a resistive element:
P = I^2R
where R is the resistance of the wire. We can calculate the resistance of the wire using its diameter and length, assuming it has a uniform cross-sectional area:
A = πr^2 = π(0.5 mm)^2 = 0.196 mm^2
R = ρL/A = (nickel resistivity) x (length of wire) / (cross-sectional area)
= (7.8 x 10^-7 Ω m) x (0.3 m) / (0.196 x 10^-6 m^2)
= 1.2 Ω
Thus, the power being dissipated in the wire is:
P = I^2R = (195 A)^2 x 1.2 Ω = 45.54 kW
Finally, we can calculate the voltage at burnout:
V = P/I = 45.54 kW / 195 A = 233.5 V
Therefore, the voltage at burnout is 233.5 V.
P = VI
where P is power, V is voltage, and I is current. At burnout, the power being dissipated in the wire is equal to the power being supplied by the electrical source, which we can assume to be constant. Thus:
P = VI = constant
We can rearrange this equation to solve for V:
V = P/I
To find the power being dissipated in the wire, we can use the equation for power in a resistive element:
P = I^2R
where R is the resistance of the wire. We can calculate the resistance of the wire using its diameter and length, assuming it has a uniform cross-sectional area:
A = πr^2 = π(0.5 mm)^2 = 0.196 mm^2
R = ρL/A = (nickel resistivity) x (length of wire) / (cross-sectional area)
= (7.8 x 10^-7 Ω m) x (0.3 m) / (0.196 x 10^-6 m^2)
= 1.2 Ω
Thus, the power being dissipated in the wire is:
P = I^2R = (195 A)^2 x 1.2 Ω = 45.54 kW
Finally, we can calculate the voltage at burnout:
V = P/I = 45.54 kW / 195 A = 233.5 V
Therefore, the voltage at burnout is 233.5 V.
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A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal in water at atmospheric pressure. At burnout, the wire has a current of 195 A. Calculate the voltage at burnout. The relevant thermos-physical properties arepf(fluid) = 959.52 kg/m3pg(vapor) = 0.597 kg/m3hf g= 2257000 J/kgσ = 0.0533 N/ma)6.15 Vb)7.15 Vc)8.15 Vd)9.15 VCorrect answer is option 'B'. Can you explain this answer?
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A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal in water at atmospheric pressure. At burnout, the wire has a current of 195 A. Calculate the voltage at burnout. The relevant thermos-physical properties arepf(fluid) = 959.52 kg/m3pg(vapor) = 0.597 kg/m3hf g= 2257000 J/kgσ = 0.0533 N/ma)6.15 Vb)7.15 Vc)8.15 Vd)9.15 VCorrect answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal in water at atmospheric pressure. At burnout, the wire has a current of 195 A. Calculate the voltage at burnout. The relevant thermos-physical properties arepf(fluid) = 959.52 kg/m3pg(vapor) = 0.597 kg/m3hf g= 2257000 J/kgσ = 0.0533 N/ma)6.15 Vb)7.15 Vc)8.15 Vd)9.15 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal in water at atmospheric pressure. At burnout, the wire has a current of 195 A. Calculate the voltage at burnout. The relevant thermos-physical properties arepf(fluid) = 959.52 kg/m3pg(vapor) = 0.597 kg/m3hf g= 2257000 J/kgσ = 0.0533 N/ma)6.15 Vb)7.15 Vc)8.15 Vd)9.15 VCorrect answer is option 'B'. Can you explain this answer?.
A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal in water at atmospheric pressure. At burnout, the wire has a current of 195 A. Calculate the voltage at burnout. The relevant thermos-physical properties arepf(fluid) = 959.52 kg/m3pg(vapor) = 0.597 kg/m3hf g= 2257000 J/kgσ = 0.0533 N/ma)6.15 Vb)7.15 Vc)8.15 Vd)9.15 VCorrect answer is option 'B'. Can you explain this answer? for Chemical Engineering 2024 is part of Chemical Engineering preparation. The Question and answers have been prepared according to the Chemical Engineering exam syllabus. Information about A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal in water at atmospheric pressure. At burnout, the wire has a current of 195 A. Calculate the voltage at burnout. The relevant thermos-physical properties arepf(fluid) = 959.52 kg/m3pg(vapor) = 0.597 kg/m3hf g= 2257000 J/kgσ = 0.0533 N/ma)6.15 Vb)7.15 Vc)8.15 Vd)9.15 VCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Chemical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal in water at atmospheric pressure. At burnout, the wire has a current of 195 A. Calculate the voltage at burnout. The relevant thermos-physical properties arepf(fluid) = 959.52 kg/m3pg(vapor) = 0.597 kg/m3hf g= 2257000 J/kgσ = 0.0533 N/ma)6.15 Vb)7.15 Vc)8.15 Vd)9.15 VCorrect answer is option 'B'. Can you explain this answer?.
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A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal in water at atmospheric pressure. At burnout, the wire has a current of 195 A. Calculate the voltage at burnout. The relevant thermos-physical properties arepf(fluid) = 959.52 kg/m3pg(vapor) = 0.597 kg/m3hf g= 2257000 J/kgσ = 0.0533 N/ma)6.15 Vb)7.15 Vc)8.15 Vd)9.15 VCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal in water at atmospheric pressure. At burnout, the wire has a current of 195 A. Calculate the voltage at burnout. The relevant thermos-physical properties arepf(fluid) = 959.52 kg/m3pg(vapor) = 0.597 kg/m3hf g= 2257000 J/kgσ = 0.0533 N/ma)6.15 Vb)7.15 Vc)8.15 Vd)9.15 VCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A 1.0 mm diameter and 300 mm long nickel wire is submerged horizontal in water at atmospheric pressure. At burnout, the wire has a current of 195 A. Calculate the voltage at burnout. The relevant thermos-physical properties arepf(fluid) = 959.52 kg/m3pg(vapor) = 0.597 kg/m3hf g= 2257000 J/kgσ = 0.0533 N/ma)6.15 Vb)7.15 Vc)8.15 Vd)9.15 VCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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