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The population of a town as per census records were 2,00, 000; 2,10,000 and 2, 30, 000 forthe year 1981, 1991 and 2001 respectively. Find the population of the town in the year 2011 using arithmetic mean method. The answer is
  • a)
    240000
  • b)
    245000
  • c)
    250000
  • d)
    255000
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The population of a town as per census records were 2,00, 000; 2,10,00...
Arithmetic mean method is used to predict the population of a town in future years based on the population data of previous years. The formula for arithmetic mean method is:

Population of future year = [(Population of last year - Population of first year) ÷ (Number of years between last year and first year)] × Number of years after last year + Population of last year

Using this formula, we can find the population of the town in the year 2011 as follows:

First year = 1981
Population in first year = 200000

Last year = 2001
Population in last year = 230000

Number of years between last year and first year = 20

Number of years after last year = 10

Population of 2011 = [(230000 - 200000) ÷ 20] × 10 + 230000
Population of 2011 = [(30000) ÷ 20] × 10 + 230000
Population of 2011 = (1500) × 10 + 230000
Population of 2011 = 15000 + 230000
Population of 2011 = 245000

Therefore, the population of the town in the year 2011 using arithmetic mean method is 245000. Option B is the correct answer.
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Community Answer
The population of a town as per census records were 2,00, 000; 2,10,00...
Po =230000
n =1
Xavg. =15000
Pn=230000+1×15000 =245000
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