A man can throw stone with initial speed of 10 metre per second . Find...
Calculating Maximum Horizontal Distance
To calculate the maximum horizontal distance that the man can throw the stone in a room of height h, we need to use the equations of motion. We can assume that the stone is thrown horizontally with an initial velocity of 10 meters per second.
Equations of Motion
The equations of motion are:
- Vertical displacement: h = ut + 1/2gt^2
- Vertical velocity: v = u + gt
- Horizontal displacement: s = ut
- Time: t = 2h/g
Where:
- u = initial velocity in the horizontal direction (10 m/s)
- g = acceleration due to gravity (9.8 m/s^2)
- s = horizontal displacement
- h = height of the room
Solving for Maximum Horizontal Distance
Substituting the values into the equations of motion, we get:
- Vertical displacement: h = 0 + 1/2(9.8)t^2
- Vertical velocity: v = 0 + 9.8t
- Horizontal displacement: s = 10(2h/g)
- Time: t = sqrt(2h/g)
Substituting the value of t into the equation for horizontal displacement, we get:
s = 10(2h/g)sqrt(2h/g)
Simplifying, we get:
s = 20sqrt(h/g)
Calculating for h = 2m
Substituting the value of h into the equation for maximum horizontal distance, we get:
s = 20sqrt(2/9.8)
Simplifying, we get:
s = 8.16 meters
Explanation
The maximum horizontal distance that the man can throw the stone in a room of height 2 meters is 8.16 meters. This means that if the room were 8.16 meters long, the stone would hit the opposite wall. The height of the room is not a factor in the calculation of the maximum horizontal distance, only the initial velocity of the stone and the acceleration due to gravity.