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A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -
- a)The maximum displacement in the direction of initial velocity is 10 m
- b)The distance travelled in first 3 seconds is 7.5 m
- c)The distance travelled in first 3 seconds is 12.5 m
- d)The distance travelled in first 3 seconds is 17.5 m
Correct answer is option 'A,C'. Can you explain this answer?
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Verified Answer
A particle has intial velocity 10 m/s. It moves due to constant retard...
The displacement of the particle is till the final velocity becomes zero. so,applying
v^2-u^2=2a s we get s=10m
Now, frm the equation s=ut - 1/2a t^2 we get that final velocity becomes zero at time t=2 sec
v^2-u^2=2a s we get s=10m
Now, frm the equation s=ut - 1/2a t^2 we get that final velocity becomes zero at time t=2 sec
So the distance travelled is
s(at 3rd sec)+10=u - a/2(2n-1) [here n is 3]
after putting all the values we get
s=12.5m
Most Upvoted Answer
A particle has intial velocity 10 m/s. It moves due to constant retard...
The displacement of the particle is till the final velocity becomes zero. so,applying
v^2-u^2=2a s we get s=10m
Now, frm the equation s=ut - 1/2a t^2 we get that final velocity becomes zero at time t=2 sec
So the distance travelled is
s(at 3rd sec)+10=u - a/2(2n-1) [here n is 3]
after putting all the values we get
s=12.5m
v^2-u^2=2a s we get s=10m
Now, frm the equation s=ut - 1/2a t^2 we get that final velocity becomes zero at time t=2 sec
So the distance travelled is
s(at 3rd sec)+10=u - a/2(2n-1) [here n is 3]
after putting all the values we get
s=12.5m
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Community Answer
A particle has intial velocity 10 m/s. It moves due to constant retard...
Explanation:
To solve this problem, we need to use the equations of motion. The particle has an initial velocity of 10 m/s and is subjected to a constant retarding force, which produces a retardation of 5 m/s^2. We need to find the maximum displacement in the direction of the initial velocity and the distance travelled in the first 3 seconds.
Maximum Displacement:
The maximum displacement occurs when the particle comes to rest. We can use the equation of motion to find the time taken for the particle to come to rest.
Using the equation of motion:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.
In this case, the final velocity (v) is 0 m/s, the initial velocity (u) is 10 m/s, and the acceleration (a) is -5 m/s^2 (retardation).
0 = 10 + (-5)t
Solving for t:
t = 10/5
t = 2 seconds
Now, we can find the maximum displacement using the equation of motion:
s = ut + (1/2)at^2
where s is the displacement.
Using the values:
u = 10 m/s
t = 2 seconds
a = -5 m/s^2
s = 10(2) + (1/2)(-5)(2)^2
s = 20 - 10
s = 10 m
Therefore, the maximum displacement in the direction of the initial velocity is 10 m. (Option A is correct)
Distance Travelled in the First 3 Seconds:
To find the distance travelled in the first 3 seconds, we need to consider the motion in two parts: the time taken to come to rest and the time after coming to rest.
1. Time taken to come to rest (t = 2 seconds):
Using the equation of motion:
s = ut + (1/2)at^2
s = 10(2) + (1/2)(-5)(2)^2
s = 20 - 10
s = 10 m
2. Time after coming to rest (t = 3 seconds - 2 seconds = 1 second):
The particle is at rest, so the distance travelled is 0.
Therefore, the total distance travelled in the first 3 seconds is 10 m. (Option C is correct)
To solve this problem, we need to use the equations of motion. The particle has an initial velocity of 10 m/s and is subjected to a constant retarding force, which produces a retardation of 5 m/s^2. We need to find the maximum displacement in the direction of the initial velocity and the distance travelled in the first 3 seconds.
Maximum Displacement:
The maximum displacement occurs when the particle comes to rest. We can use the equation of motion to find the time taken for the particle to come to rest.
Using the equation of motion:
v = u + at
where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time taken.
In this case, the final velocity (v) is 0 m/s, the initial velocity (u) is 10 m/s, and the acceleration (a) is -5 m/s^2 (retardation).
0 = 10 + (-5)t
Solving for t:
t = 10/5
t = 2 seconds
Now, we can find the maximum displacement using the equation of motion:
s = ut + (1/2)at^2
where s is the displacement.
Using the values:
u = 10 m/s
t = 2 seconds
a = -5 m/s^2
s = 10(2) + (1/2)(-5)(2)^2
s = 20 - 10
s = 10 m
Therefore, the maximum displacement in the direction of the initial velocity is 10 m. (Option A is correct)
Distance Travelled in the First 3 Seconds:
To find the distance travelled in the first 3 seconds, we need to consider the motion in two parts: the time taken to come to rest and the time after coming to rest.
1. Time taken to come to rest (t = 2 seconds):
Using the equation of motion:
s = ut + (1/2)at^2
s = 10(2) + (1/2)(-5)(2)^2
s = 20 - 10
s = 10 m
2. Time after coming to rest (t = 3 seconds - 2 seconds = 1 second):
The particle is at rest, so the distance travelled is 0.
Therefore, the total distance travelled in the first 3 seconds is 10 m. (Option C is correct)
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A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer?
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A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer?.
A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer?.
Solutions for A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 11.
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A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer?, a detailed solution for A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer? has been provided alongside types of A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A particle has intial velocity 10 m/s. It moves due to constant retarding force along the line of velocity which produces a retardation of 5 m/s2. Then -a)The maximum displacement in the direction of initial velocity is 10 mb)The distance travelled in first 3 seconds is 7.5 mc)The distance travelled in first 3 seconds is 12.5 md)The distance travelled in first 3 seconds is 17.5 mCorrect answer is option 'A,C'. Can you explain this answer? tests, examples and also practice Class 11 tests.
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