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Two particles A and B are moving in the same direction on same straight line a is ahead of B by 20m and A has constant speed 5M per second and B has initial speed 30 M per second and retardation of 10 M per second square then if x is a total distance travelled by B as it meets a for the second time then value of X is?
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Two particles A and B are moving in the same direction on same straigh...
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Two particles A and B are moving in the same direction on same straigh...
Solution:
Given:
Initial distance between A and B, d = 20 m
Speed of A, u1 = 5 m/s
Initial speed of B, u2 = 30 m/s
Retardation of B, a = -10 m/s^2
To find:
The total distance travelled by B as it meets A for the second time, x.
Let's assume that after time t, B meets A for the second time.
After time t, the distance covered by A, S1 = u1t
The distance covered by B, S2 = u2t + 1/2at^2
As both A and B meet at the same point, S1 = S2 + d
u1t = u2t + 1/2at^2 + d
Simplify the above equation, we get
1/2at^2 + (u2 - u1)t + d = 0
On solving the above quadratic equation, we get
t = [-(u2 - u1) ± sqrt((u2 - u1)^2 - 4(1/2a)d)]/2(1/2a)
t = [-(30 - 5) ± sqrt((30 - 5)^2 - 4(1/2(-10))(20))]/2(1/2(-10))
t = 3 seconds (ignoring negative value)
Now, the distance covered by B in 3 seconds is given by
x = u2t + 1/2at^2
x = 30(3) + 1/2(-10)(3)^2
x = 75 m
Therefore, the total distance travelled by B as it meets A for the second time is 75 m.
Final Answer: x = 75 m
Given:
Initial distance between A and B, d = 20 m
Speed of A, u1 = 5 m/s
Initial speed of B, u2 = 30 m/s
Retardation of B, a = -10 m/s^2
To find:
The total distance travelled by B as it meets A for the second time, x.
Let's assume that after time t, B meets A for the second time.
After time t, the distance covered by A, S1 = u1t
The distance covered by B, S2 = u2t + 1/2at^2
As both A and B meet at the same point, S1 = S2 + d
u1t = u2t + 1/2at^2 + d
Simplify the above equation, we get
1/2at^2 + (u2 - u1)t + d = 0
On solving the above quadratic equation, we get
t = [-(u2 - u1) ± sqrt((u2 - u1)^2 - 4(1/2a)d)]/2(1/2a)
t = [-(30 - 5) ± sqrt((30 - 5)^2 - 4(1/2(-10))(20))]/2(1/2(-10))
t = 3 seconds (ignoring negative value)
Now, the distance covered by B in 3 seconds is given by
x = u2t + 1/2at^2
x = 30(3) + 1/2(-10)(3)^2
x = 75 m
Therefore, the total distance travelled by B as it meets A for the second time is 75 m.
Final Answer: x = 75 m
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Two particles A and B are moving in the same direction on same straight line a is ahead of B by 20m and A has constant speed 5M per second and B has initial speed 30 M per second and retardation of 10 M per second square then if x is a total distance travelled by B as it meets a for the second time then value of X is?
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Two particles A and B are moving in the same direction on same straight line a is ahead of B by 20m and A has constant speed 5M per second and B has initial speed 30 M per second and retardation of 10 M per second square then if x is a total distance travelled by B as it meets a for the second time then value of X is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two particles A and B are moving in the same direction on same straight line a is ahead of B by 20m and A has constant speed 5M per second and B has initial speed 30 M per second and retardation of 10 M per second square then if x is a total distance travelled by B as it meets a for the second time then value of X is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two particles A and B are moving in the same direction on same straight line a is ahead of B by 20m and A has constant speed 5M per second and B has initial speed 30 M per second and retardation of 10 M per second square then if x is a total distance travelled by B as it meets a for the second time then value of X is?.
Two particles A and B are moving in the same direction on same straight line a is ahead of B by 20m and A has constant speed 5M per second and B has initial speed 30 M per second and retardation of 10 M per second square then if x is a total distance travelled by B as it meets a for the second time then value of X is? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about Two particles A and B are moving in the same direction on same straight line a is ahead of B by 20m and A has constant speed 5M per second and B has initial speed 30 M per second and retardation of 10 M per second square then if x is a total distance travelled by B as it meets a for the second time then value of X is? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two particles A and B are moving in the same direction on same straight line a is ahead of B by 20m and A has constant speed 5M per second and B has initial speed 30 M per second and retardation of 10 M per second square then if x is a total distance travelled by B as it meets a for the second time then value of X is?.
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Two particles A and B are moving in the same direction on same straight line a is ahead of B by 20m and A has constant speed 5M per second and B has initial speed 30 M per second and retardation of 10 M per second square then if x is a total distance travelled by B as it meets a for the second time then value of X is?, a detailed solution for Two particles A and B are moving in the same direction on same straight line a is ahead of B by 20m and A has constant speed 5M per second and B has initial speed 30 M per second and retardation of 10 M per second square then if x is a total distance travelled by B as it meets a for the second time then value of X is? has been provided alongside types of Two particles A and B are moving in the same direction on same straight line a is ahead of B by 20m and A has constant speed 5M per second and B has initial speed 30 M per second and retardation of 10 M per second square then if x is a total distance travelled by B as it meets a for the second time then value of X is? theory, EduRev gives you an
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