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If ionization potential for hydrogen atom is 13.6 eV, then ionization potential for He+ will be
- a)54.4 eV
- b)6.8 eV [1993]
- c)13.6 eV
- d)24.5 eV
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
If ionization potential for hydrogen atom is 13.6 eV, then ionization ...
The ionization energy of any hydrogen like species (having one electron only) is given by the equation
Since the atomic number of H is 1 and that of He is 2, therefore, the I.E. of He+ is four times (22) the I.E. of H i.e., 13.6 × 4 = 54.4 eV
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If ionization potential for hydrogen atom is 13.6 eV, then ionization ...
Explanation:
The ionization potential is defined as the amount of energy required to remove an electron from an atom or ion in its ground state. It is usually given in electron volts (eV).
The ionization potential for the hydrogen atom is given as 13.6 eV. This means that it takes 13.6 eV of energy to remove an electron from a hydrogen atom in its ground state.
Now, let's consider the ionization potential for the helium atom. Helium has two electrons in its ground state. The first electron in helium is in the 1s orbital, which is the same orbital as the electron in hydrogen. Therefore, the ionization potential for the first electron in helium should be the same as that for hydrogen, which is 13.6 eV.
However, once the first electron is removed from helium, the remaining electron experiences a different effective nuclear charge due to the presence of only one electron in the atom. This results in a different ionization potential for the second electron.
To calculate the ionization potential for the second electron in helium, we can use the concept of effective nuclear charge. The effective nuclear charge is the net positive charge experienced by an electron in a multi-electron atom. It can be approximated as the atomic number (Z) minus the number of shielding electrons.
In the case of helium, the effective nuclear charge experienced by the second electron is approximately +1. This is because the two electrons in helium repel each other, reducing the net positive charge felt by the second electron.
The ionization potential for the second electron in helium can be calculated using the Rydberg formula:
Ionization potential = 13.6 eV * (Z^2 / n^2),
where Z is the effective nuclear charge and n is the principal quantum number. For the second electron in helium, Z = 1 and n = 2.
Plugging in the values, we get:
Ionization potential = 13.6 eV * (1^2 / 2^2) = 13.6 eV * (1/4) = 3.4 eV.
Therefore, the ionization potential for the second electron in helium is 3.4 eV.
To find the total ionization potential for helium, we add the ionization potentials for both electrons:
Total ionization potential = 13.6 eV + 3.4 eV = 17 eV.
Therefore, the correct answer is option A: 54.4 eV.
The ionization potential is defined as the amount of energy required to remove an electron from an atom or ion in its ground state. It is usually given in electron volts (eV).
The ionization potential for the hydrogen atom is given as 13.6 eV. This means that it takes 13.6 eV of energy to remove an electron from a hydrogen atom in its ground state.
Now, let's consider the ionization potential for the helium atom. Helium has two electrons in its ground state. The first electron in helium is in the 1s orbital, which is the same orbital as the electron in hydrogen. Therefore, the ionization potential for the first electron in helium should be the same as that for hydrogen, which is 13.6 eV.
However, once the first electron is removed from helium, the remaining electron experiences a different effective nuclear charge due to the presence of only one electron in the atom. This results in a different ionization potential for the second electron.
To calculate the ionization potential for the second electron in helium, we can use the concept of effective nuclear charge. The effective nuclear charge is the net positive charge experienced by an electron in a multi-electron atom. It can be approximated as the atomic number (Z) minus the number of shielding electrons.
In the case of helium, the effective nuclear charge experienced by the second electron is approximately +1. This is because the two electrons in helium repel each other, reducing the net positive charge felt by the second electron.
The ionization potential for the second electron in helium can be calculated using the Rydberg formula:
Ionization potential = 13.6 eV * (Z^2 / n^2),
where Z is the effective nuclear charge and n is the principal quantum number. For the second electron in helium, Z = 1 and n = 2.
Plugging in the values, we get:
Ionization potential = 13.6 eV * (1^2 / 2^2) = 13.6 eV * (1/4) = 3.4 eV.
Therefore, the ionization potential for the second electron in helium is 3.4 eV.
To find the total ionization potential for helium, we add the ionization potentials for both electrons:
Total ionization potential = 13.6 eV + 3.4 eV = 17 eV.
Therefore, the correct answer is option A: 54.4 eV.
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If ionization potential for hydrogen atom is 13.6 eV, then ionization potential for He+ will bea)54.4 eVb)6.8 eV [1993]c)13.6 eVd)24.5 eVCorrect answer is option 'A'. Can you explain this answer?
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