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An element , X has the following isotopic composition : [2007] 200X : 90% 199X : 8.0 % 202X : 2.0 %
The weighted average atomic mass of the naturally occuring element X is closest to
The weighted average atomic mass of the naturally occuring element X is closest to
- a)201 amu
- b)202 amu
- c)199 amu
- d)200 amu
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
An element , X has the following isotopic composition : [2007] 200X : ...
Average isotopic mass of
199.96 amuMost Upvoted Answer
An element , X has the following isotopic composition : [2007] 200X : ...
The weighted average atomic mass of an element is calculated by considering the abundance of each isotope and its respective atomic mass.
Given isotopic composition:
- 200X: 90%
- 199X: 8.0%
- 202X: 2.0%
To calculate the weighted average atomic mass, we multiply the abundance of each isotope by its atomic mass, and then sum them up.
Let's perform the calculations:
Atomic mass of 200X = 200 amu
Atomic mass of 199X = 199 amu
Atomic mass of 202X = 202 amu
Weighted average atomic mass = (abundance of 200X * atomic mass of 200X) + (abundance of 199X * atomic mass of 199X) + (abundance of 202X * atomic mass of 202X)
= (0.90 * 200 amu) + (0.08 * 199 amu) + (0.02 * 202 amu)
= 180 amu + 15.92 amu + 4.04 amu
= 200.96 amu
The calculated weighted average atomic mass is closest to 201 amu, which is not one of the given options.
However, we can see that the atomic mass of 200X is the closest to the calculated value of 200.96 amu. Therefore, the correct answer is option 'D' - 200 amu.
Given isotopic composition:
- 200X: 90%
- 199X: 8.0%
- 202X: 2.0%
To calculate the weighted average atomic mass, we multiply the abundance of each isotope by its atomic mass, and then sum them up.
Let's perform the calculations:
Atomic mass of 200X = 200 amu
Atomic mass of 199X = 199 amu
Atomic mass of 202X = 202 amu
Weighted average atomic mass = (abundance of 200X * atomic mass of 200X) + (abundance of 199X * atomic mass of 199X) + (abundance of 202X * atomic mass of 202X)
= (0.90 * 200 amu) + (0.08 * 199 amu) + (0.02 * 202 amu)
= 180 amu + 15.92 amu + 4.04 amu
= 200.96 amu
The calculated weighted average atomic mass is closest to 201 amu, which is not one of the given options.
However, we can see that the atomic mass of 200X is the closest to the calculated value of 200.96 amu. Therefore, the correct answer is option 'D' - 200 amu.
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Community Answer
An element , X has the following isotopic composition : [2007] 200X : ...
D is correct.
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