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What volume of oxygen gas (O2) measured at 0°C and 1 atm, is needed to burn completely 1L of propane gas (C3H8) measured under the same conditions ? [2008]
- a)7 L
- b)6 L
- c)5 L
- d)10 L
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
What volume of oxygen gas (O2) measured at 0°C and 1 atm, is neede...
Writing the equation of combustion of propane (C3H8), we get
From the above equation we find that we need 5 L of oxygen at NTP to completely burn 1 L of propane at N.T.P.
If we change the conditions for both the gases from N.T.P. to same conditions of temperature and pressure. The same results are obtained. i.e. 5 L is the correct answer.
If we change the conditions for both the gases from N.T.P. to same conditions of temperature and pressure. The same results are obtained. i.e. 5 L is the correct answer.
Most Upvoted Answer
What volume of oxygen gas (O2) measured at 0°C and 1 atm, is neede...
°C and 1 atm pressure is produced by the decomposition of 10 grams of potassium chlorate (KClO3)?
The balanced chemical equation for the decomposition of potassium chlorate is:
2KClO3(s) → 2KCl(s) + 3O2(g)
From the equation, we can see that for every 2 moles of KClO3 that decompose, 3 moles of O2 gas are produced.
First, we need to calculate the number of moles of KClO3 in 10 grams:
molar mass of KClO3 = 39.98 g/mol + 35.45 g/mol + 3(16.00 g/mol) = 122.55 g/mol
moles of KClO3 = mass / molar mass = 10 g / 122.55 g/mol = 0.0816 mol
Since 2 moles of KClO3 produce 3 moles of O2, we can calculate the number of moles of O2 produced:
moles of O2 = (3/2) x moles of KClO3 = (3/2) x 0.0816 mol = 0.1224 mol
Now we can use the ideal gas law to calculate the volume of O2 produced:
PV = nRT
where P = 1 atm, V = volume of O2 gas, n = 0.1224 mol, R = 0.0821 L·atm/mol·K (the gas constant), and T = 273 K (0°C + 273).
Solving for V, we get:
V = nRT/P = (0.1224 mol)(0.0821 L·atm/mol·K)(273 K)/(1 atm) = 2.74 L
Therefore, 10 grams of KClO3 will produce 2.74 liters of O2 gas at 0°C and 1 atm pressure.
The balanced chemical equation for the decomposition of potassium chlorate is:
2KClO3(s) → 2KCl(s) + 3O2(g)
From the equation, we can see that for every 2 moles of KClO3 that decompose, 3 moles of O2 gas are produced.
First, we need to calculate the number of moles of KClO3 in 10 grams:
molar mass of KClO3 = 39.98 g/mol + 35.45 g/mol + 3(16.00 g/mol) = 122.55 g/mol
moles of KClO3 = mass / molar mass = 10 g / 122.55 g/mol = 0.0816 mol
Since 2 moles of KClO3 produce 3 moles of O2, we can calculate the number of moles of O2 produced:
moles of O2 = (3/2) x moles of KClO3 = (3/2) x 0.0816 mol = 0.1224 mol
Now we can use the ideal gas law to calculate the volume of O2 produced:
PV = nRT
where P = 1 atm, V = volume of O2 gas, n = 0.1224 mol, R = 0.0821 L·atm/mol·K (the gas constant), and T = 273 K (0°C + 273).
Solving for V, we get:
V = nRT/P = (0.1224 mol)(0.0821 L·atm/mol·K)(273 K)/(1 atm) = 2.74 L
Therefore, 10 grams of KClO3 will produce 2.74 liters of O2 gas at 0°C and 1 atm pressure.
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What volume of oxygen gas (O2) measured at 0°C and 1 atm, is needed to burn completely 1L of propane gas (C3H8) measured under the same conditions ? [2008]a)7 Lb)6 Lc)5 Ld)10 LCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about What volume of oxygen gas (O2) measured at 0°C and 1 atm, is needed to burn completely 1L of propane gas (C3H8) measured under the same conditions ? [2008]a)7 Lb)6 Lc)5 Ld)10 LCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What volume of oxygen gas (O2) measured at 0°C and 1 atm, is needed to burn completely 1L of propane gas (C3H8) measured under the same conditions ? [2008]a)7 Lb)6 Lc)5 Ld)10 LCorrect answer is option 'C'. Can you explain this answer?.
What volume of oxygen gas (O2) measured at 0°C and 1 atm, is needed to burn completely 1L of propane gas (C3H8) measured under the same conditions ? [2008]a)7 Lb)6 Lc)5 Ld)10 LCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about What volume of oxygen gas (O2) measured at 0°C and 1 atm, is needed to burn completely 1L of propane gas (C3H8) measured under the same conditions ? [2008]a)7 Lb)6 Lc)5 Ld)10 LCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What volume of oxygen gas (O2) measured at 0°C and 1 atm, is needed to burn completely 1L of propane gas (C3H8) measured under the same conditions ? [2008]a)7 Lb)6 Lc)5 Ld)10 LCorrect answer is option 'C'. Can you explain this answer?.
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