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An organic compound contains carbon , hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be : [2008]
- a)CH3O
- b)CH2O
- c)CHO
- d)CH4O
Correct answer is option 'A'. Can you explain this answer?
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Verified Answer
An organic compound contains carbon , hydrogen and oxygen. Its element...
Thus empirical formula is CH3O.
Most Upvoted Answer
An organic compound contains carbon , hydrogen and oxygen. Its element...
To determine the empirical formula of the organic compound, we need to find the simplest ratio of the atoms present in the compound.
Given:
% Carbon (C) = 38.71%
% Hydrogen (H) = 9.67%
% Oxygen (O) = 100 - 38.71 - 9.67 = 51.62%
Step 1: Convert the percentages to grams.
Assuming we have 100g of the compound, we can convert the percentages to grams:
C = 38.71g
H = 9.67g
O = 51.62g
Step 2: Determine the number of moles of each element.
To determine the number of moles, we divide the mass of each element by its molar mass.
The molar mass of carbon (C) is 12.01 g/mol, hydrogen (H) is 1.01 g/mol, and oxygen (O) is 16.00 g/mol.
moles of C = 38.71g / 12.01 g/mol = 3.225 mol
moles of H = 9.67g / 1.01 g/mol = 9.579 mol
moles of O = 51.62g / 16.00 g/mol = 3.226 mol
Step 3: Divide the number of moles by the smallest number of moles.
The smallest number of moles is 3.225 mol (from carbon).
moles of C = 3.225 mol / 3.225 mol = 1 mol
moles of H = 9.579 mol / 3.225 mol ≈ 2.97 mol
moles of O = 3.226 mol / 3.225 mol ≈ 1 mol
Step 4: Write the empirical formula.
The empirical formula is the simplest whole number ratio of the atoms present in the compound.
The ratio of C:H:O is approximately 1:2.97:1.
To simplify the ratio, we can round the ratio to the nearest whole number:
1:3:1
The empirical formula of the compound is CH3O, which matches option A.
Given:
% Carbon (C) = 38.71%
% Hydrogen (H) = 9.67%
% Oxygen (O) = 100 - 38.71 - 9.67 = 51.62%
Step 1: Convert the percentages to grams.
Assuming we have 100g of the compound, we can convert the percentages to grams:
C = 38.71g
H = 9.67g
O = 51.62g
Step 2: Determine the number of moles of each element.
To determine the number of moles, we divide the mass of each element by its molar mass.
The molar mass of carbon (C) is 12.01 g/mol, hydrogen (H) is 1.01 g/mol, and oxygen (O) is 16.00 g/mol.
moles of C = 38.71g / 12.01 g/mol = 3.225 mol
moles of H = 9.67g / 1.01 g/mol = 9.579 mol
moles of O = 51.62g / 16.00 g/mol = 3.226 mol
Step 3: Divide the number of moles by the smallest number of moles.
The smallest number of moles is 3.225 mol (from carbon).
moles of C = 3.225 mol / 3.225 mol = 1 mol
moles of H = 9.579 mol / 3.225 mol ≈ 2.97 mol
moles of O = 3.226 mol / 3.225 mol ≈ 1 mol
Step 4: Write the empirical formula.
The empirical formula is the simplest whole number ratio of the atoms present in the compound.
The ratio of C:H:O is approximately 1:2.97:1.
To simplify the ratio, we can round the ratio to the nearest whole number:
1:3:1
The empirical formula of the compound is CH3O, which matches option A.
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An organic compound contains carbon , hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be : [2008]a)CH3Ob)CH2Oc)CHOd)CH4OCorrect answer is option 'A'. Can you explain this answer?
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An organic compound contains carbon , hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be : [2008]a)CH3Ob)CH2Oc)CHOd)CH4OCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An organic compound contains carbon , hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be : [2008]a)CH3Ob)CH2Oc)CHOd)CH4OCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound contains carbon , hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be : [2008]a)CH3Ob)CH2Oc)CHOd)CH4OCorrect answer is option 'A'. Can you explain this answer?.
An organic compound contains carbon , hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be : [2008]a)CH3Ob)CH2Oc)CHOd)CH4OCorrect answer is option 'A'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An organic compound contains carbon , hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be : [2008]a)CH3Ob)CH2Oc)CHOd)CH4OCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An organic compound contains carbon , hydrogen and oxygen. Its elemental analysis gave C, 38.71% and H, 9.67%. The empirical formula of the compound would be : [2008]a)CH3Ob)CH2Oc)CHOd)CH4OCorrect answer is option 'A'. Can you explain this answer?.
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