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Let PQRSTU be a regular hexagon. The ratio of the area of the triangle PRT to that of the hexagon PQRSTU is
  • a)
    0.3
  • b)
    0.5
  • c)
    1
  • d)
    None of the above
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Let PQRSTU be a regular hexagon. The ratio of the area of the triangle...
It's given that PQRSTU is a regular hexagon and O is the center of the hexagon.
If we fold TSR , PQR , TUP along lines TR, PR, PT respectively then vertices S,Q,U will overlap each other exactly at center of the hexagon.
Hence we can say that Area of hexagon PQRSTU =  2( PRT)
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Most Upvoted Answer
Let PQRSTU be a regular hexagon. The ratio of the area of the triangle...
Solution:

Given, PQRSTU is a regular hexagon.

To find: The ratio of the area of the triangle PRT to that of the hexagon PQRSTU.

Let a be the side of the hexagon.

Area of the hexagon PQRSTU = 6 × (1/2) × a^2 × (√3/2) = 3√3a^2 sq units.

In a regular hexagon, the diagonal of one triangle is the side of the hexagon.

So, PR = a.

Let M be the midpoint of PQ, then PM = MQ = (a/2).

Also, angle TPM = angle TQM = 60°.

Therefore, triangle TPM and TQM are congruent.

So, TP = TQ = a/2.

Then, the area of triangle PRT = (1/2) × PR × TP = (1/2) × a × a/2 = a^2/4 sq units.

So, the required ratio = area of triangle PRT/ area of hexagon PQRSTU

= (a^2/4)/(3√3a^2)

= 1/(4√3)

= (√3/12)

= 0.5 (approx)

Hence, the correct option is (B) 0.5.
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Let PQRSTU be a regular hexagon. The ratio of the area of the triangle PRT to that of the hexagon PQRSTU isa)0.3b)0.5c)1d)None of the aboveCorrect answer is option 'B'. Can you explain this answer?
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