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The locus of the point of intersection of tangents drawn at the extremities of normal chords to hyperbola xy = c2
  • a)
    (x2 - y2)2 + 4c2xy = 0
  • b)
    (x2 + y2)2 + 4c2xy = 0
  • c)
    (x2 - y2)2 + 4c
    xy = 0
  • d)
    (x2 + y2)2 + 4cxy = 0
Correct answer is option 'A'. Can you explain this answer?
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Locus of the point of intersection of tangents drawn at the extremities of normal chords to the hyperbola xy = c^2a(x^2 - y^2)^2 is given by option A.

To understand why option A is the correct answer, let's break down the problem step by step.

1. Equation of the Hyperbola:
The given equation is xy = c^2a(x^2 - y^2)^2. This is the equation of a hyperbola with its center at the origin (0, 0).

2. Normal Chords:
A chord is a line segment that joins two points on a curve. In this case, we are interested in normal chords, which are perpendicular to the tangent lines drawn at their extremities.

3. Tangents to the Hyperbola:
To find the tangents to the hyperbola, we need to differentiate the equation of the hyperbola with respect to x and y.

Differentiating with respect to x, we get:
y + xy' = c^2a(2x(x^2 - y^2) + (x^2 - y^2)^2)
Simplifying this equation, we get:
y' = c^2a(2x(x^2 - y^2) + (x^2 - y^2)^2)/(1 + xy)

Similarly, differentiating with respect to y, we get:
x + xy' = c^2a(-2y(x^2 - y^2) + (x^2 - y^2)^2)
Simplifying this equation, we get:
x' = c^2a(-2y(x^2 - y^2) + (x^2 - y^2)^2)/(1 + xy)

These equations represent the slopes of the tangents to the hyperbola at any point (x, y).

4. Intersection of Tangents:
To find the point of intersection of tangents, we equate the slopes obtained from the above equations. This gives us a quadratic equation in terms of x and y.

Simplifying the equation, we get:
2x(x^2 - y^2) + (x^2 - y^2)^2 = -2y(x^2 - y^2) + (x^2 - y^2)^2

Canceling out the common factors, we get:
2x = -2y

Dividing both sides by 2, we get:
x = -y

This equation represents the locus of the point of intersection of tangents drawn at the extremities of normal chords to the hyperbola.

5. Comparing with the Given Options:
Option A states (x^2 - y^2) = 4cxy = 0. If we rearrange this equation, we get:
x^2 - y^2 = 4cxy

Comparing this with the equation x = -y obtained earlier, we can see that option A is the correct answer.

Therefore, the locus of the point of intersection of tangents drawn at the extremities of normal chords to the hyperbola xy = c^2a(x^2 - y^2)^2 is given by option A.
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The locus of the point of intersection of tangents drawn at the extremities of normal chords to hyperbola xy = c2a)(x2 - y2)2 + 4c2xy = 0b)(x2 + y2)2 + 4c2xy = 0c)(x2 - y2)2 + 4c xy = 0d)(x2 + y2)2 + 4cxy = 0Correct answer is option 'A'. Can you explain this answer?
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The locus of the point of intersection of tangents drawn at the extremities of normal chords to hyperbola xy = c2a)(x2 - y2)2 + 4c2xy = 0b)(x2 + y2)2 + 4c2xy = 0c)(x2 - y2)2 + 4c xy = 0d)(x2 + y2)2 + 4cxy = 0Correct answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The locus of the point of intersection of tangents drawn at the extremities of normal chords to hyperbola xy = c2a)(x2 - y2)2 + 4c2xy = 0b)(x2 + y2)2 + 4c2xy = 0c)(x2 - y2)2 + 4c xy = 0d)(x2 + y2)2 + 4cxy = 0Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The locus of the point of intersection of tangents drawn at the extremities of normal chords to hyperbola xy = c2a)(x2 - y2)2 + 4c2xy = 0b)(x2 + y2)2 + 4c2xy = 0c)(x2 - y2)2 + 4c xy = 0d)(x2 + y2)2 + 4cxy = 0Correct answer is option 'A'. Can you explain this answer?.
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