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The running integrator, given by             
  • a)
    has no finite singularities in its double sided Laplace Transfrom Y(s)
  • b)
    Produces a bounded output for every causal bounded input
  • c)
    Produces a bounded output for every anticausal bounded input
  • d)
    has no finite zeroes in its double sided Laplace Transfrom Y(s)
Correct answer is option 'B'. Can you explain this answer?
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The running integrator, given by a)has no finite singularities in...
Ans. (b)
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The running integrator, given by a)has no finite singularities in its double sided Laplace Transfrom Y(s)b)Produces a bounded output for every causal bounded inputc)Produces a bounded output for every anticausal bounded inputd)has no finite zeroes in its double sided Laplace Transfrom Y(s)Correct answer is option 'B'. Can you explain this answer?
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