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The relative nucleophilicity in polar, protic, solvents of the following is:
  (I) CH3OH                  (II) CH3SH                (III) CH3NH2
 
  • a)
    I > II > III 
  • b)
     II > III > I 
  • c)
    I > III > II 
  • d)
     III > I > II
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
The relative nucleophilicity in polar, protic, solvents of the followi...
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b)III < ii="" />< />
c)II < i="" />< />
d)I < ii="" />< />

Correct answer: d) I < ii="" />< />

Explanation:
In polar, protic solvents, nucleophilicity is generally directly proportional to basicity. The stronger the basicity of a species, the stronger its ability to donate a pair of electrons and act as a nucleophile.

Among the given species, CH3NH2 has the highest basicity due to the presence of a lone pair of electrons on the nitrogen atom. It can donate this lone pair easily and act as a strong nucleophile. Hence, it is the most nucleophilic species among the given options.

Next comes CH3SH, which is less basic than CH3NH2 but still more basic than CH3OH. Sulfur is less electronegative than oxygen, which makes the lone pair of electrons on the sulfur more available for donation. Hence, CH3SH is a stronger nucleophile than CH3OH.

Finally, CH3OH has the lowest basicity among the given options. Its lone pair of electrons is involved in hydrogen bonding with the solvent molecules, which reduces its availability for donation. Hence, it is the least nucleophilic species among the given options.
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Community Answer
The relative nucleophilicity in polar, protic, solvents of the followi...
Because sulphur has more no. lone pair as compared to nh3 and oh
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