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For the set of equations
x1 + 2x  + x3 + 4x4 = 0
3x1 + 6x2 + 3x3 + 12x4 = 0
  • a)
    Only the trivial solution x1 = x2 = x3 = x4 = 0 exists.
  • b)
    There are no solutions.
  • c)
    A unique non-trivial solution exists.
  • d)
    Multiple non-trivial solutions exist
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
For the set of equationsx1 + 2x+ x3+ 4x4 = 03x1 + 6x2 + 3x3 + 12x4 = 0...
(d)
Because number of unknowns more them no. of equation.
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Most Upvoted Answer
For the set of equationsx1 + 2x+ x3+ 4x4 = 03x1 + 6x2 + 3x3 + 12x4 = 0...
Solution:
To determine the solution of the given set of equations, we can write them in matrix form as follows:

Ax = 0

where

A = [1 2 0 4; 3 6 3 12]
x = [x1; x2; x3; x4]

Rank of Matrix A:
The rank of matrix A can be determined using row reduction as follows:

A = [1 2 0 4; 3 6 3 12]
R2 = R2 - 3R1
A = [1 2 0 4; 0 0 3 0]

The matrix A has rank 2, which is less than the number of unknowns (4). Therefore, there are infinitely many solutions or no solutions.

Homogeneous System of Equations:
The given set of equations is homogeneous, i.e., the right-hand side of each equation is zero. Therefore, the trivial solution x1 = x2 = x3 = x4 = 0 is always a solution.

Non-Trivial Solutions:
Since the rank of matrix A is less than 4, there are infinitely many solutions or no solutions. To determine if there are non-trivial solutions, we can use the reduced row echelon form of matrix A as follows:

A = [1 2 0 4; 0 0 3 0]
R1 = R1 - 2R2
A = [1 2 0 4; 0 0 1 0]
R1 = R1 - 4R2
A = [1 2 0 0; 0 0 1 0]

The last row corresponds to the equation x3 = 0. Substituting this into the first row, we get x1 + 2x2 = 0 or x1 = -2x2. Therefore, the general solution can be written as:

x1 = -2t
x2 = t
x3 = 0
x4 = 0

where t is any scalar. This shows that there are infinitely many non-trivial solutions.

Conclusion:
The correct option is (D) Multiple non-trivial solutions exist.
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For the set of equationsx1 + 2x+ x3+ 4x4 = 03x1 + 6x2 + 3x3 + 12x4 = 0a)Only the trivial solution x1 = x2 = x3 = x4 = 0 exists.b)There are no solutions.c)A unique non-trivial solution exists.d)Multiple non-trivial solutions existCorrect answer is option 'D'. Can you explain this answer?
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