Mechanical Engineering Exam > Mechanical Engineering Questions > What is not the condition for the equilibrium...
Start Learning for Free
What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?
- a)∑Fx=0
- b)∑Fy=0
- c)∑Fz=0
- d)∑F≠0
Correct answer is option 'D'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
What is not the condition for the equilibrium in calculations involved...
For the equilibrium in the three dimensional system of axis we have all the conditions true as, ∑Fx=0, ∑Fy=0 and ∑Fz=0. Also we have the summation of the forces equal to zero. Which is not a non-zero value.
Most Upvoted Answer
What is not the condition for the equilibrium in calculations involved...
Explanation:
Conditions for equilibrium in calculations involved in the determination of the centre of mass:
- ∑Fx=0: This condition states that the sum of all forces acting in the x-direction must be zero for equilibrium. This ensures that there is no net force causing any acceleration in the x-direction.
- ∑Fy=0: This condition states that the sum of all forces acting in the y-direction must be zero for equilibrium. This ensures that there is no net force causing any acceleration in the y-direction.
- ∑Fz=0: This condition states that the sum of all forces acting in the z-direction must be zero for equilibrium. This ensures that there is no net force causing any acceleration in the z-direction.
Not a condition for equilibrium:
- ∑F≠0: This statement is not a condition for equilibrium. In fact, the sum of all forces acting on an object must be zero for equilibrium, not unequal to zero. If the sum of forces is not zero, the object will accelerate in the direction of the resultant force.
Therefore, the correct answer is option 'D' as it does not represent a condition for equilibrium in calculations involved in the determination of the centre of mass.
Conditions for equilibrium in calculations involved in the determination of the centre of mass:
- ∑Fx=0: This condition states that the sum of all forces acting in the x-direction must be zero for equilibrium. This ensures that there is no net force causing any acceleration in the x-direction.
- ∑Fy=0: This condition states that the sum of all forces acting in the y-direction must be zero for equilibrium. This ensures that there is no net force causing any acceleration in the y-direction.
- ∑Fz=0: This condition states that the sum of all forces acting in the z-direction must be zero for equilibrium. This ensures that there is no net force causing any acceleration in the z-direction.
Not a condition for equilibrium:
- ∑F≠0: This statement is not a condition for equilibrium. In fact, the sum of all forces acting on an object must be zero for equilibrium, not unequal to zero. If the sum of forces is not zero, the object will accelerate in the direction of the resultant force.
Therefore, the correct answer is option 'D' as it does not represent a condition for equilibrium in calculations involved in the determination of the centre of mass.
Attention Mechanical Engineering Students!
To make sure you are not studying endlessly, EduRev has designed Mechanical Engineering study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Mechanical Engineering.
|
Explore Courses for Mechanical Engineering exam
|
|
Top Courses for Mechanical EngineeringView all
What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer?
Question Description
What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer?.
What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer? for Mechanical Engineering 2024 is part of Mechanical Engineering preparation. The Question and answers have been prepared according to the Mechanical Engineering exam syllabus. Information about What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Mechanical Engineering 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer?.
Solutions for What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Mechanical Engineering.
Download more important topics, notes, lectures and mock test series for Mechanical Engineering Exam by signing up for free.
Here you can find the meaning of What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer?, a detailed solution for What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer? has been provided alongside types of What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice What is not the condition for the equilibrium in calculations involved in the determination of the centre of mass?a)∑Fx=0b)∑Fy=0c)∑Fz=0d)∑F≠0Correct answer is option 'D'. Can you explain this answer? tests, examples and also practice Mechanical Engineering tests.
|
|
Explore Courses for Mechanical Engineering exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup