The line passing through the extremely A of the major axis and extremi...
Explanation:
The given ellipse equation is x^2 + 9y^2 = 9, which can be written as x^2/9 + y^2/1 = 1. This ellipse has a major axis of length 6 (2a = 6) and a minor axis of length 2 (2b = 2).
Finding the Endpoints of Major and Minor Axes:
- The endpoints of the major axis are (3, 0) and (-3, 0) denoted by points A and A'.
- The endpoints of the minor axis are (0, 1) and (0, -1) denoted by points B and B'.
Finding the Point of Intersection with Auxiliary Circle:
- The auxiliary circle of the ellipse has the equation x^2 + y^2 = 1.
- Substituting the equation of the ellipse into the auxiliary circle equation, we get x^2 + 9y^2 = 9 = x^2 + y^2.
- Solving the above equation gives y^2 = 1/10, which implies y = ±1/√10.
- Therefore, the points of intersection are (3, 1/√10) and (3, -1/√10) denoted by M and M'.
Calculating the Area of the Triangle:
- The area of the triangle with vertices A, M, and the origin O can be calculated using the formula for the area of a triangle given by half the magnitude of the cross product of vectors AM and AO.
- The vector AM is (3, 1/√10) and the vector AO is (-3, 0).
- Calculating the cross product magnitude gives |AM x AO| = |3(0) - (1/√10)(-3)| = 3/√10.
- Therefore, the area of the triangle is 1/2 * base * height = 1/2 * 3 * 3/√10 = 9/2√10 = 9√10/20 = 9/10.
- So, the correct answer is option 'D' (27/10).
The line passing through the extremely A of the major axis and extremi...