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A thin semi-circular ring of radius r has a positive charge q distributed uniformly over it. The net field the centre is 
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A thin semi-circular ring of radius r has a positive charge q distribu...
FORMULA USED :

E = λ/(2πε0r)

EXPLANATION :

+ve charge of magnitude q is distributed uniformly over the surface. As the charge is on the surface only we can consider it a line charge. so λ = q/πr.

Now see that the electric field lines due to to the positive charge on the surface are directed towards the centre that is in downwards direction. therefore in vector notation, (-j) will be used.

Now substituting the value in the formula,

E = -q/(2πε0r(πr)) j^

=> E = - q/2π²ε0r² j^
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Community Answer
A thin semi-circular ring of radius r has a positive charge q distribu...
Let us consider a differential element dl. charge on this element.

Electric field at O due to dq is
Th e compon ent dE cos θ will be coun ter bala n ced by another element on left portion. Hence resultant field at O is the resultant of the component dE sinθ only.

The direction of E is towards negative y-axis.
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