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Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from point P lying on  Locus of circumcentre of triangle PAB is 
  • a)
    4x2 + 4xy - 6x + 10 y - 10 = 0
  • b)
    4x2 - 4xy - 6x + 10 y - 10 = 0
  • c)
    4x2 + 4xy + 6x + 10 y - 10 = 0
  • d)
    none of these 
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from po...
 now if centre of circle is(5, 7) ≡ C say then PACB is a cyclic quadrilateral, so circumcentre of triangle PAB is midpoint of PC i.e. 



⇒ 4x2 - 4xy - 6xy + 10y - 10 = 0
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Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from po...
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Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from point P lying onLocus of circumcentre of triangle PAB isa)4x2 + 4xy - 6x + 10 y - 10 = 0b)4x2 - 4xy - 6x + 10 y - 10 = 0c)4x2 + 4xy + 6x + 10 y - 10 = 0d)none of theseCorrect answer is option 'B'. Can you explain this answer?
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Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from point P lying onLocus of circumcentre of triangle PAB isa)4x2 + 4xy - 6x + 10 y - 10 = 0b)4x2 - 4xy - 6x + 10 y - 10 = 0c)4x2 + 4xy + 6x + 10 y - 10 = 0d)none of theseCorrect answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from point P lying onLocus of circumcentre of triangle PAB isa)4x2 + 4xy - 6x + 10 y - 10 = 0b)4x2 - 4xy - 6x + 10 y - 10 = 0c)4x2 + 4xy + 6x + 10 y - 10 = 0d)none of theseCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from point P lying onLocus of circumcentre of triangle PAB isa)4x2 + 4xy - 6x + 10 y - 10 = 0b)4x2 - 4xy - 6x + 10 y - 10 = 0c)4x2 + 4xy + 6x + 10 y - 10 = 0d)none of theseCorrect answer is option 'B'. Can you explain this answer?.
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Here you can find the meaning of Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from point P lying onLocus of circumcentre of triangle PAB isa)4x2 + 4xy - 6x + 10 y - 10 = 0b)4x2 - 4xy - 6x + 10 y - 10 = 0c)4x2 + 4xy + 6x + 10 y - 10 = 0d)none of theseCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from point P lying onLocus of circumcentre of triangle PAB isa)4x2 + 4xy - 6x + 10 y - 10 = 0b)4x2 - 4xy - 6x + 10 y - 10 = 0c)4x2 + 4xy + 6x + 10 y - 10 = 0d)none of theseCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from point P lying onLocus of circumcentre of triangle PAB isa)4x2 + 4xy - 6x + 10 y - 10 = 0b)4x2 - 4xy - 6x + 10 y - 10 = 0c)4x2 + 4xy + 6x + 10 y - 10 = 0d)none of theseCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from point P lying onLocus of circumcentre of triangle PAB isa)4x2 + 4xy - 6x + 10 y - 10 = 0b)4x2 - 4xy - 6x + 10 y - 10 = 0c)4x2 + 4xy + 6x + 10 y - 10 = 0d)none of theseCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice Tangents PA and PB are drawn to circle (x - 5)2 + (y - 7)2 = 1 from point P lying onLocus of circumcentre of triangle PAB isa)4x2 + 4xy - 6x + 10 y - 10 = 0b)4x2 - 4xy - 6x + 10 y - 10 = 0c)4x2 + 4xy + 6x + 10 y - 10 = 0d)none of theseCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice JEE tests.
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