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The diameter of droplet is 0.075 mm. What is the intensity of the pressure (N/sq. cm) developed in the droplet by surface tension of 0.000075 N/mm?
  • a)
    0.4
  • b)
    0.6
  • c)
    0.8
  • d)
    1
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
The diameter of droplet is 0.075 mm. What is the intensity of the pres...
Intensity of Pressure
6 = Surface tension
D = Diameter of droplet
ΔP = 0.4 N/cm2
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Most Upvoted Answer
The diameter of droplet is 0.075 mm. What is the intensity of the pres...
Given:
Diameter of droplet = 0.075 mm
Surface tension = 0.000075 N/mm

To find:
Intensity of pressure (N/sq. cm)

Formula:
Intensity of pressure = Surface tension/Radius

Calculation:
Radius = Diameter/2 = 0.0375 mm
Radius in meter = 0.0375/1000 = 0.0000375 m

Intensity of pressure = 0.000075/0.0000375 = 2 N/sq. m

Converting N/m^2 to N/cm^2, we get:
Intensity of pressure = 2/10,000 = 0.0002 N/cm^2

Converting N/cm^2 to N/sq. cm, we get:
Intensity of pressure = 0.0002 x 10000 = 0.4 N/sq. cm

Therefore, the intensity of pressure developed in the droplet by surface tension is 0.4 N/sq. cm, which is option A.
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The diameter of droplet is 0.075 mm. What is the intensity of the pressure (N/sq. cm) developed in the droplet by surface tension of 0.000075 N/mm?a)0.4b)0.6c)0.8d)1Correct answer is option 'A'. Can you explain this answer?
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