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A black body of 0.2 m2 area has an effective temperature of 800 K. Calculate the intensity of normal radiations
  • a)
    1234.65 W/m2 sr
  • b)
    7396.28 W/m2 sr
  • c)
    3476.74 W/m2 sr
  • d)
    8739.43 W/m2 sr
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A black body of 0.2 m2area has an effective temperature of 800 K. Calc...
I= α T 4/π = 7396.28 W/m2 sr.
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Most Upvoted Answer
A black body of 0.2 m2area has an effective temperature of 800 K. Calc...
Calculation of Intensity of Normal Radiations from a Black Body

Given data:
Area of the black body (A) = 0.2 m^2
Effective temperature of the black body (T) = 800 K

Formula used:
Stefan-Boltzmann Law states that the power radiated per unit area of a black body is proportional to the fourth power of its absolute temperature. The formula for the intensity of normal radiation (I) emitted by a black body is given as:

I = σT^4

Where,
σ = Stefan-Boltzmann constant = 5.67 x 10^-8 W/m^2K^4

Calculation:
Substituting the given values in the formula of I, we get:

I = 5.67 x 10^-8 x (800)^4
I = 7396.28 W/m^2sr

Therefore, the intensity of normal radiation emitted by the black body is 7396.28 W/m^2sr.

Final Answer:
The correct option is B) 7396.28 W/m^2sr.
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Community Answer
A black body of 0.2 m2area has an effective temperature of 800 K. Calc...
Calculate the intensity of normal radiations at 60degree how to solve it sir
give me the answer
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