A block A is released from the top of smooth inclined plane and slides...
Consider a block of mass m lying on a frictionless inclined plane of length AB = L, height = h and angle of inclination θ.
When the block is released, it moves down the plane under a force mg sin θ.
Hence the acceleration of the block down the plane is
a = g sin θ
If the block starts from rest from point A, then its velocity when it reaches the bottom B is given by
v
2 – u
2 = 2as
v
2 – 0 = 2aL
For the block which falls vertically downward of height, h:
So, speed of both the blocks will be same.
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A block A is released from the top of smooth inclined plane and slides...
Explanation:
When a block is released from the top of a smooth inclined plane, it will slide down the plane due to the force of gravity. On the other hand, when a block is dropped vertically downwards, it will also fall due to the force of gravity. Let's analyze the motion of each block separately.
Block A sliding down the inclined plane:
- The force acting on block A is its weight, which can be resolved into two components: one parallel to the inclined plane (mg*sinθ) and one perpendicular to the inclined plane (mg*cosθ).
- The component of the weight parallel to the inclined plane (mg*sinθ) will cause the block to accelerate down the plane.
- The acceleration of block A can be calculated using the equation a = g*sinθ, where g is the acceleration due to gravity and θ is the angle of inclination.
- The speed of block A at any point can be calculated using the equation v = u + at, where u is the initial speed (0 in this case), a is the acceleration, and t is the time taken.
- As the block slides down the inclined plane, it will gain speed and reach the bottom of the plane in a certain time.
Block B falling vertically downwards:
- When block B is dropped vertically downwards, it will fall due to the force of gravity.
- The only force acting on block B is its weight, which is mg, where m is the mass of the block and g is the acceleration due to gravity.
- The acceleration of block B is equal to the acceleration due to gravity, which is approximately 9.8 m/s².
- The speed of block B at any point can be calculated using the equation v = u + at, where u is the initial speed (0 in this case), a is the acceleration, and t is the time taken.
- As block B falls vertically downwards, it will gain speed and reach the ground in a certain time.
Comparison between the two blocks:
- Both blocks are subject to the same acceleration due to gravity.
- The time taken for both blocks to reach the ground will be the same because the acceleration due to gravity is the same and the distance traveled is also the same (assuming the height of the inclined plane and the height from which block B is dropped are the same).
- However, the speed at which both blocks reach the ground will be different.
- Block A will reach the ground with a higher speed than block B because it has been accelerating down the inclined plane, whereas block B has been falling vertically downwards without any additional acceleration.
Therefore, the correct statement is that both blocks will reach the ground with the same speed (option C).
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