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Given: [2009]

Electrode potential, Eo for the reaction,  will be :
  • a)
    0.90 V
  • b)
    0.30 V
  • c)
    0.38 V
  • d)
    0.52 V
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Given: [2009]Electrode potential, Eo for the reaction, will be :a)0.90...
   = – 2 × F × 0.337
 = – 0.674 F        ....(i)
  = – 1 × F × – 0.153
  =  0.153 F     ....(ii)
On adding eqn (i) & (ii)
Here n = 1       Δ Eo = + 0.52 V
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