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An ellipsoidal cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Then
  • a)
    electric field near A in the cavity = electric field near B in the cavity
  • b)
    charge density at A = charge density at B
  • c)
    potential at A = potential at B
  • d)
    total electric field flux through the surface of the cavity is q/ε0
Correct answer is option 'C,D'. Can you explain this answer?
Verified Answer
An ellipsoidal cavity is carved within a perfect conductor. A positive...
When two points are connected with a conducting path in electrostatic condition, then the potential of the two points is equal. Thus potential at A = Potential at B (c) is the correct option.
Option (d) is a result of Gauss's law
Total electric flux through cavity
Option (a) and (b) are dependent on the curvature which is different at points A and B.
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An ellipsoidal cavity is carved within a perfect conductor. A positive...
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An ellipsoidal cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Thena)electric field near A in the cavity = electric field near B in the cavityb)charge density at A = charge density at Bc)potential at A = potential at Bd)total electric field flux through the surface of the cavity is q/ε0Correct answer is option 'C,D'. Can you explain this answer?
Question Description
An ellipsoidal cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Thena)electric field near A in the cavity = electric field near B in the cavityb)charge density at A = charge density at Bc)potential at A = potential at Bd)total electric field flux through the surface of the cavity is q/ε0Correct answer is option 'C,D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An ellipsoidal cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Thena)electric field near A in the cavity = electric field near B in the cavityb)charge density at A = charge density at Bc)potential at A = potential at Bd)total electric field flux through the surface of the cavity is q/ε0Correct answer is option 'C,D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An ellipsoidal cavity is carved within a perfect conductor. A positive charge q is placed at the centre of the cavity. The points A and B are on the cavity surface as shown in the figure. Thena)electric field near A in the cavity = electric field near B in the cavityb)charge density at A = charge density at Bc)potential at A = potential at Bd)total electric field flux through the surface of the cavity is q/ε0Correct answer is option 'C,D'. Can you explain this answer?.
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