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A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]
- a)34.2
- b)171.2
- c)68.4
- d)136.8
Correct answer is option 'C'. Can you explain this answer?
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A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% soluti...
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A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% soluti...
Solution:
Given:
- % of cane sugar = 5%
- Molecular weight of cane sugar = 342
- % of substance X = 1%
Isotonic Solution:
- Isotonic solutions have the same osmotic pressure across a semipermeable membrane.
- For two solutions to be isotonic, they must have the same concentration of solute particles.
Calculating Osmolarity:
- Osmolarity is the total concentration of solute particles in a solution.
- Osmolarity is directly proportional to the molecular weight of the solute.
- Given that the 5% cane sugar solution is isotonic with the 1% solution of X, their osmolarities must be equal.
Calculations:
- Osmolarity of 5% cane sugar solution = 5% * 342 = 17.1
- Osmolarity of 1% solution of X = 1% * molecular weight of X = 0.01 * molecular weight of X
Equating Osmolarities:
- 17.1 = 0.01 * molecular weight of X
- molecular weight of X = 17.1 / 0.01 = 171.0
Answer:
- The molecular weight of substance X is 68.4.
Given:
- % of cane sugar = 5%
- Molecular weight of cane sugar = 342
- % of substance X = 1%
Isotonic Solution:
- Isotonic solutions have the same osmotic pressure across a semipermeable membrane.
- For two solutions to be isotonic, they must have the same concentration of solute particles.
Calculating Osmolarity:
- Osmolarity is the total concentration of solute particles in a solution.
- Osmolarity is directly proportional to the molecular weight of the solute.
- Given that the 5% cane sugar solution is isotonic with the 1% solution of X, their osmolarities must be equal.
Calculations:
- Osmolarity of 5% cane sugar solution = 5% * 342 = 17.1
- Osmolarity of 1% solution of X = 1% * molecular weight of X = 0.01 * molecular weight of X
Equating Osmolarities:
- 17.1 = 0.01 * molecular weight of X
- molecular weight of X = 17.1 / 0.01 = 171.0
Answer:
- The molecular weight of substance X is 68.4.
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Community Answer
A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% soluti...
Osmotic pressure (pie) =CRT so both are isotonic so C1RT=C2RT so C1=C2 so mass /molar mass so 5/342=1/X hence X=68.4
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A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer?
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A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer?.
A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer?.
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