Class 12 Exam > Class 12 Questions > A 5% solution of cane sugar (mol. wt. =342) i...
Start Learning for Free
A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]
- a)34.2
- b)171.2
- c)68.4
- d)136.8
Correct answer is option 'C'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% soluti...
Most Upvoted Answer
A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% soluti...
Solution:
Given:
- % of cane sugar = 5%
- Molecular weight of cane sugar = 342
- % of substance X = 1%
Isotonic Solution:
- Isotonic solutions have the same osmotic pressure across a semipermeable membrane.
- For two solutions to be isotonic, they must have the same concentration of solute particles.
Calculating Osmolarity:
- Osmolarity is the total concentration of solute particles in a solution.
- Osmolarity is directly proportional to the molecular weight of the solute.
- Given that the 5% cane sugar solution is isotonic with the 1% solution of X, their osmolarities must be equal.
Calculations:
- Osmolarity of 5% cane sugar solution = 5% * 342 = 17.1
- Osmolarity of 1% solution of X = 1% * molecular weight of X = 0.01 * molecular weight of X
Equating Osmolarities:
- 17.1 = 0.01 * molecular weight of X
- molecular weight of X = 17.1 / 0.01 = 171.0
Answer:
- The molecular weight of substance X is 68.4.
Given:
- % of cane sugar = 5%
- Molecular weight of cane sugar = 342
- % of substance X = 1%
Isotonic Solution:
- Isotonic solutions have the same osmotic pressure across a semipermeable membrane.
- For two solutions to be isotonic, they must have the same concentration of solute particles.
Calculating Osmolarity:
- Osmolarity is the total concentration of solute particles in a solution.
- Osmolarity is directly proportional to the molecular weight of the solute.
- Given that the 5% cane sugar solution is isotonic with the 1% solution of X, their osmolarities must be equal.
Calculations:
- Osmolarity of 5% cane sugar solution = 5% * 342 = 17.1
- Osmolarity of 1% solution of X = 1% * molecular weight of X = 0.01 * molecular weight of X
Equating Osmolarities:
- 17.1 = 0.01 * molecular weight of X
- molecular weight of X = 17.1 / 0.01 = 171.0
Answer:
- The molecular weight of substance X is 68.4.
Free Test
FREE
| Start Free Test |
Community Answer
A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% soluti...
Osmotic pressure (pie) =CRT so both are isotonic so C1RT=C2RT so C1=C2 so mass /molar mass so 5/342=1/X hence X=68.4
|
Explore Courses for Class 12 exam
|
|
Similar Class 12 Doubts
A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer?
Question Description
A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer?.
A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? for Class 12 2024 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 12 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer?.
Solutions for A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 12.
Download more important topics, notes, lectures and mock test series for Class 12 Exam by signing up for free.
Here you can find the meaning of A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer?, a detailed solution for A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? has been provided alongside types of A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A 5% solution of cane sugar (mol. wt. =342) is isotonic with 1% solution of a substance X. The molecular weight of X is [1998]a)34.2b)171.2c)68.4d)136.8Correct answer is option 'C'. Can you explain this answer? tests, examples and also practice Class 12 tests.
|
|
Explore Courses for Class 12 exam
|
|
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup