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A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :
- a)V
- b)2V
- c)4V
- d)– 2V
Correct answer is option 'A'. Can you explain this answer?
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A solid conducting sphere having a charge Q is surrounded by an unchar...
The potential inside the shell will be the sa me everywhere as on its surface. As we add – 3Q charge on the surface, the potential on the surface changes by the same amount as that inside. Therefore the potential difference remains the same.
Most Upvoted Answer
A solid conducting sphere having a charge Q is surrounded by an unchar...
Let the charge given to the shell be Q'. Since the shell is an uncharged conductor, the charge will distribute itself uniformly over the outer surface of the shell.
The potential difference between two points is given by the equation V = k(Q/r), where k is the electrostatic constant and r is the distance between the two points.
Initially, the potential difference between the surface of the solid sphere and the outer surface of the hollow shell is V.
When the shell is given a charge Q', the total charge on the system is Q + Q'.
The potential difference between the surface of the solid sphere and the outer surface of the hollow shell can be calculated as follows:
V' = k((Q + Q')/r)
Since the charge on the solid sphere remains unchanged, Q + Q' = Q.
V' = k(Q/r)
Therefore, the potential difference remains the same, V.
So, even after giving a charge Q' to the shell, the potential difference between the surface of the solid sphere and the outer surface of the hollow shell remains V.
The potential difference between two points is given by the equation V = k(Q/r), where k is the electrostatic constant and r is the distance between the two points.
Initially, the potential difference between the surface of the solid sphere and the outer surface of the hollow shell is V.
When the shell is given a charge Q', the total charge on the system is Q + Q'.
The potential difference between the surface of the solid sphere and the outer surface of the hollow shell can be calculated as follows:
V' = k((Q + Q')/r)
Since the charge on the solid sphere remains unchanged, Q + Q' = Q.
V' = k(Q/r)
Therefore, the potential difference remains the same, V.
So, even after giving a charge Q' to the shell, the potential difference between the surface of the solid sphere and the outer surface of the hollow shell remains V.
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A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer?
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A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer?.
A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer?.
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