JEE Exam > JEE Questions > A solid conducting sphere having a charge Q i...
Start Learning for Free
A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :
- a)V
- b)2V
- c)4V
- d)– 2V
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
A solid conducting sphere having a charge Q is surrounded by an unchar...
The potential inside the shell will be the sa me everywhere as on its surface. As we add – 3Q charge on the surface, the potential on the surface changes by the same amount as that inside. Therefore the potential difference remains the same.
Most Upvoted Answer
A solid conducting sphere having a charge Q is surrounded by an unchar...
Let the charge given to the shell be Q'. Since the shell is an uncharged conductor, the charge will distribute itself uniformly over the outer surface of the shell.
The potential difference between two points is given by the equation V = k(Q/r), where k is the electrostatic constant and r is the distance between the two points.
Initially, the potential difference between the surface of the solid sphere and the outer surface of the hollow shell is V.
When the shell is given a charge Q', the total charge on the system is Q + Q'.
The potential difference between the surface of the solid sphere and the outer surface of the hollow shell can be calculated as follows:
V' = k((Q + Q')/r)
Since the charge on the solid sphere remains unchanged, Q + Q' = Q.
V' = k(Q/r)
Therefore, the potential difference remains the same, V.
So, even after giving a charge Q' to the shell, the potential difference between the surface of the solid sphere and the outer surface of the hollow shell remains V.
The potential difference between two points is given by the equation V = k(Q/r), where k is the electrostatic constant and r is the distance between the two points.
Initially, the potential difference between the surface of the solid sphere and the outer surface of the hollow shell is V.
When the shell is given a charge Q', the total charge on the system is Q + Q'.
The potential difference between the surface of the solid sphere and the outer surface of the hollow shell can be calculated as follows:
V' = k((Q + Q')/r)
Since the charge on the solid sphere remains unchanged, Q + Q' = Q.
V' = k(Q/r)
Therefore, the potential difference remains the same, V.
So, even after giving a charge Q' to the shell, the potential difference between the surface of the solid sphere and the outer surface of the hollow shell remains V.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer?
Question Description
A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer?.
A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer?.
Solutions for A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A solid conducting sphere having a charge Q is surrounded by an uncharged concentric conducting hollow spherical shell. Let the potential difference between the surface of the solid sphere and that of the outer surface of the hollow shell be V. If the shell is now given a charge of – 3Q, the new potential difference between the same two surfaces is :a)Vb)2Vc)4Vd)– 2VCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup