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Two equal negative charges –q are fixed at points (0, – a) and (0, a) on y – axis. A positive charge Q is released from rest at the point (2a, 0) on the x - axis. The charge Q will
  • a)
    execute simple harmonic motion about the origin
  • b)
    move to the origin remain at rest
  • c)
    move to infinity
  • d)
    execute oscillatory but not simple harmonic motion
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Two equal negative charges –q are fixed at points (0, – a)...
Let us consider the positive charge Q at any instant of time t at a distance x from the origin. It is under the influence of two forces   On resolving these two forces we find that F sin θ cancels out. The resultant force is
FR = 2F cos θ

Since FR is not proportional to x, the motion is NOT simple harmonic. The charge Q will accelerate till the origin and gain velocity. At the origin the net force is zero but due to momentum it will cross the origin and more towards left. As it comes on negative x-axis, the force is again towards the origin.   
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Two equal negative charges –q are fixed at points (0, – a)...
Repel each other.
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Two equal negative charges –q are fixed at points (0, – a) and (0, a) on y – axis. A positive charge Q is released from rest at the point (2a, 0) on the x - axis. The charge Q willa)execute simple harmonic motion about the originb)move to the origin remain at restc)move to infinityd)execute oscillatory but not simple harmonic motionCorrect answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Two equal negative charges –q are fixed at points (0, – a) and (0, a) on y – axis. A positive charge Q is released from rest at the point (2a, 0) on the x - axis. The charge Q willa)execute simple harmonic motion about the originb)move to the origin remain at restc)move to infinityd)execute oscillatory but not simple harmonic motionCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Two equal negative charges –q are fixed at points (0, – a) and (0, a) on y – axis. A positive charge Q is released from rest at the point (2a, 0) on the x - axis. The charge Q willa)execute simple harmonic motion about the originb)move to the origin remain at restc)move to infinityd)execute oscillatory but not simple harmonic motionCorrect answer is option 'D'. Can you explain this answer?.
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