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The ring M1 and the block M2 are held in position shown in figure now the system is released if M1 greater than m to find V1 V2 and the name them one side down on the smooth a fixed vertical rod by the distance h?
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The ring M1 and the block M2 are held in position shown in figure now ...
Analysis of the System:
- The system consists of a ring M1 and a block M2 held in position as shown in the figure.
- The system is released, and M1 is greater than M2.

Finding the Velocities:
- As the system is released, both M1 and M2 will start moving downwards due to gravity.
- The acceleration of both masses can be determined using Newton's second law:
- For M1: M1 * a = M1 * g - T (1)
- For M2: M2 * a = T - M2 * g (2)
- Solving equations (1) and (2) simultaneously, we can find the acceleration 'a'.
- Once the acceleration is known, the velocities V1 and V2 can be calculated using the equations:
- V1 = √(2 * a * h)
- V2 = √(2 * a * h)

Distance from the Rod:
- The distances traveled by M1 and M2 can be calculated using the formulas:
- Distance traveled by M1 = h - (1/2) * a * t^2
- Distance traveled by M2 = (1/2) * a * t^2
- The distances will give the final positions of M1 and M2 from the rod.
By following these steps, you can determine the velocities V1 and V2 of the ring and block, as well as their final positions from the fixed vertical rod.
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The ring M1 and the block M2 are held in position shown in figure now the system is released if M1 greater than m to find V1 V2 and the name them one side down on the smooth a fixed vertical rod by the distance h?
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