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A box of mass m is released from rest at position on the frictionless curved track shown. It slides a distance d along the track in time t to reach position 2, dropping a vertical distance h. Let v and a be the instantaneous speed and instantaneous acceleration, respectively, of the box at position 2. Which of the following equations is valid for this situation?
                                           
  • a)
    h = vt
  • b)
    h = (1/2)gt2
  • c)
    mgh = (1/2)mv2
  • d)
    none
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A box of mass m is released from rest at position on the frictionless ...
According to the Work Energy Theorem,
Change in PE = Change in KE
So, mgh = ½ mv2 
Hence C
Forum id- 1775160
For complete circle v = √(5gl)
mgh = ½mv2
So, h = 2.5R
View all questions of this test
Most Upvoted Answer
A box of mass m is released from rest at position on the frictionless ...
According to the Work Energy Theorem,
Change in PE = Change in KE
So, mgh = ½ mv2 
Hence C
Forum id- 1775160
For complete circle v = √(5gl)
mgh = ½mv2
So, h = 2.5R
Free Test
Community Answer
A box of mass m is released from rest at position on the frictionless ...
It is simple application of WORK--ENERGY THEOREM.
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A box of mass m is released from rest at position on the frictionless curved track shown. It slides a distance d along the track in time t to reach position 2, dropping a vertical distance h. Let v and a be the instantaneous speed and instantaneous acceleration, respectively, of the box at position 2. Which of the following equations is valid for this situation? a)h = vtb)h = (1/2)gt2c)mgh = (1/2)mv2d)noneCorrect answer is option 'C'. Can you explain this answer?
Question Description
A box of mass m is released from rest at position on the frictionless curved track shown. It slides a distance d along the track in time t to reach position 2, dropping a vertical distance h. Let v and a be the instantaneous speed and instantaneous acceleration, respectively, of the box at position 2. Which of the following equations is valid for this situation? a)h = vtb)h = (1/2)gt2c)mgh = (1/2)mv2d)noneCorrect answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A box of mass m is released from rest at position on the frictionless curved track shown. It slides a distance d along the track in time t to reach position 2, dropping a vertical distance h. Let v and a be the instantaneous speed and instantaneous acceleration, respectively, of the box at position 2. Which of the following equations is valid for this situation? a)h = vtb)h = (1/2)gt2c)mgh = (1/2)mv2d)noneCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box of mass m is released from rest at position on the frictionless curved track shown. It slides a distance d along the track in time t to reach position 2, dropping a vertical distance h. Let v and a be the instantaneous speed and instantaneous acceleration, respectively, of the box at position 2. Which of the following equations is valid for this situation? a)h = vtb)h = (1/2)gt2c)mgh = (1/2)mv2d)noneCorrect answer is option 'C'. Can you explain this answer?.
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