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Doubly ionised helium atoms and hydrogen ions are accelerated from rest through the same potential drop. The ratio of the final velocities of the helium and the hydrogen ion is [1994]
  • a)
    1/2
  • b)
    2
  • c)
    1/√2
  • d)
    √2
Correct answer is option 'D'. Can you explain this answer?
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Doubly ionised helium atoms and hydrogen ions are accelerated from res...
1/2 mv2 = eV, or, v = (2eV/m)1/2
the mass of helium ion is four times that of
hydrogen ion. Further, the charge on helium
ion is twice that of hydrogen ion.
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Doubly ionised helium atoms and hydrogen ions are accelerated from res...
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Doubly ionised helium atoms and hydrogen ions are accelerated from res...
The final velocity of an ion accelerated through a potential drop can be calculated using the formula:

vf = √(2qV/m)

where vf is the final velocity, q is the charge of the ion, V is the potential drop, and m is the mass of the ion.

For doubly ionized helium (He2+) and hydrogen (H+) ions, the charges are q = 2e and q = e, respectively, where e is the elementary charge. The masses are m = 4m_p and m = m_p, respectively, where m_p is the mass of a proton.

Therefore, the ratio of the final velocities is:

vf(He2+)/vf(H+) = √(2(2e)V/4m_p) / √(2eV/m_p)

Simplifying this expression, we get:

vf(He2+)/vf(H+) = √2

Therefore, the correct answer is (b) 2.
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Doubly ionised helium atoms and hydrogen ions are accelerated from rest through the same potential drop. The ratio of the final velocities of the helium and the hydrogen ion is [1994]a)1/2b)2c)1/√2d)√2Correct answer is option 'D'. Can you explain this answer?
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