JEE Exam > JEE Questions > A shell of mass m moving with a velocity v br...
Start Learning for Free
A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be?
Most Upvoted Answer
A shell of mass m moving with a velocity v breaks up suddenly into two...
Just conserve it's momentum as no external force is applied on the body. then you will get the final answer.
Community Answer
A shell of mass m moving with a velocity v breaks up suddenly into two...
Introduction
When a shell of mass m, moving with a velocity v, breaks into two pieces, we can analyze the situation using the principle of conservation of momentum.
Conservation of Momentum
- Momentum before the breakage = Momentum after the breakage
- Initial momentum of the shell = m * v
Breakdown of Mass
- The shell breaks into two parts:
- Part A: mass = m/3 (remains stationary)
- Part B: mass = m - m/3 = 2m/3 (moves with a new velocity)
Momentum after the Break
- Momentum after the break:
- For Part A (stationary): 0 (since its velocity = 0)
- For Part B (moving): (2m/3) * v_B (where v_B is the velocity of Part B)
Setting Up the Equation
- According to conservation of momentum:
- Initial momentum = Final momentum
- m * v = 0 + (2m/3) * v_B
Solving for Velocity
- Rearranging the equation gives us:
- m * v = (2m/3) * v_B
- Dividing both sides by (2m/3):
- v_B = (3v)/2
Conclusion
- The velocity of the part with mass 2m/3 is (3v)/2.
- This indicates that the remaining part moves in the same direction as the original shell but with a greater velocity due to the sudden breakage.
When a shell of mass m, moving with a velocity v, breaks into two pieces, we can analyze the situation using the principle of conservation of momentum.
Conservation of Momentum
- Momentum before the breakage = Momentum after the breakage
- Initial momentum of the shell = m * v
Breakdown of Mass
- The shell breaks into two parts:
- Part A: mass = m/3 (remains stationary)
- Part B: mass = m - m/3 = 2m/3 (moves with a new velocity)
Momentum after the Break
- Momentum after the break:
- For Part A (stationary): 0 (since its velocity = 0)
- For Part B (moving): (2m/3) * v_B (where v_B is the velocity of Part B)
Setting Up the Equation
- According to conservation of momentum:
- Initial momentum = Final momentum
- m * v = 0 + (2m/3) * v_B
Solving for Velocity
- Rearranging the equation gives us:
- m * v = (2m/3) * v_B
- Dividing both sides by (2m/3):
- v_B = (3v)/2
Conclusion
- The velocity of the part with mass 2m/3 is (3v)/2.
- This indicates that the remaining part moves in the same direction as the original shell but with a greater velocity due to the sudden breakage.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be?
Question Description
A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be?.
A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be?.
Solutions for A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be? defined & explained in the simplest way possible. Besides giving the explanation of
A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be?, a detailed solution for A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be? has been provided alongside types of A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be? theory, EduRev gives you an
ample number of questions to practice A shell of mass m moving with a velocity v breaks up suddenly into two pieces. The part having mass m/3 remains stationary. The velocity of other part will be? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup