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A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. What is the tension in the rope if the monkey climbs down with an acceleration of 4 ms−2
- a)200 N
- b)300 N
- c)240 N
- d)280 N
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A monkey of mass 40 kg climbs on a rope which can stand a maximum tens...
Mass of the monkey, m = 40 kg
Acceleration due to gravity, g = 10 m/s
Maximum tension that the rope can bear, Tmax = 600 N
Acceleration of the monkey, a = 4 m/s2 downward
Using Newton’s second law of motion, we can write the equation of motion as:
mg T = ma
T = m (g- a)
= 40(10-4)
= 240 N
Acceleration due to gravity, g = 10 m/s
Maximum tension that the rope can bear, Tmax = 600 N
Acceleration of the monkey, a = 4 m/s2 downward
Using Newton’s second law of motion, we can write the equation of motion as:
mg T = ma
T = m (g- a)
= 40(10-4)
= 240 N
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Community Answer
A monkey of mass 40 kg climbs on a rope which can stand a maximum tens...
Mass of the monkey, m = 40 kg
Acceleration due to gravity, g = 10 m/s
Maximum tension that the rope can bear, Tmax = 600 N
Acceleration of the monkey, a = 6 m/s2 upward
Using Newtons second law of motion, we can write the equation of motion as:
T mg = ma
T = m(g + a)
= 40 (10 + 6)
= 640 N
Since T > Tmax, the rope will break in this case.
(b)
Acceleration of the monkey, a = 4 m/s2 downward
Using Newtons second law of motion, we can write the equation of motion as:
mg T = ma
T = m (g- a)
= 40(10-4)
= 240 N
Since T < tmax, the="" rope="" will="" not="" break="" in="" this="">
(c)
The monkey is climbing with a uniform speed of 5 m/s. Therefore, its acceleration is zero, i.e., a = 0.
Using Newtons second law of motion, we can write the equation of motion as:
T - mg = ma
T- mg = 0
T = mg
= 40 × 10
= 400 N
Since T < tmax, the="" rope="" will="" not="" break="" in="" this="">
(d)
When the monkey falls freely under gravity, its will acceleration become equal to the acceleration due to gravity, i.e., a = g
Using Newtons second law of motion, we can write the equation of motion as:
mg + T = mg
T = m(g -g) = 0
Since T < tmax, the="" rope="" will="" not="" break="" in="" this="" case.="" the="" rope="" will="" not="" break="" in="" this="">
Acceleration due to gravity, g = 10 m/s
Maximum tension that the rope can bear, Tmax = 600 N
Acceleration of the monkey, a = 6 m/s2 upward
Using Newtons second law of motion, we can write the equation of motion as:
T mg = ma
T = m(g + a)
= 40 (10 + 6)
= 640 N
Since T > Tmax, the rope will break in this case.
(b)
Acceleration of the monkey, a = 4 m/s2 downward
Using Newtons second law of motion, we can write the equation of motion as:
mg T = ma
T = m (g- a)
= 40(10-4)
= 240 N
Since T < tmax, the="" rope="" will="" not="" break="" in="" this="">
(c)
The monkey is climbing with a uniform speed of 5 m/s. Therefore, its acceleration is zero, i.e., a = 0.
Using Newtons second law of motion, we can write the equation of motion as:
T - mg = ma
T- mg = 0
T = mg
= 40 × 10
= 400 N
Since T < tmax, the="" rope="" will="" not="" break="" in="" this="">
(d)
When the monkey falls freely under gravity, its will acceleration become equal to the acceleration due to gravity, i.e., a = g
Using Newtons second law of motion, we can write the equation of motion as:
mg + T = mg
T = m(g -g) = 0
Since T < tmax, the="" rope="" will="" not="" break="" in="" this="" case.="" the="" rope="" will="" not="" break="" in="" this="">
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A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. What is the tension in the rope if the monkey climbs down with an acceleration of 4 ms−2a)200 Nb)300 Nc)240 Nd)280 NCorrect answer is option 'C'. Can you explain this answer?
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A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. What is the tension in the rope if the monkey climbs down with an acceleration of 4 ms−2a)200 Nb)300 Nc)240 Nd)280 NCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. What is the tension in the rope if the monkey climbs down with an acceleration of 4 ms−2a)200 Nb)300 Nc)240 Nd)280 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. What is the tension in the rope if the monkey climbs down with an acceleration of 4 ms−2a)200 Nb)300 Nc)240 Nd)280 NCorrect answer is option 'C'. Can you explain this answer?.
A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. What is the tension in the rope if the monkey climbs down with an acceleration of 4 ms−2a)200 Nb)300 Nc)240 Nd)280 NCorrect answer is option 'C'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. What is the tension in the rope if the monkey climbs down with an acceleration of 4 ms−2a)200 Nb)300 Nc)240 Nd)280 NCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. What is the tension in the rope if the monkey climbs down with an acceleration of 4 ms−2a)200 Nb)300 Nc)240 Nd)280 NCorrect answer is option 'C'. Can you explain this answer?.
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A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. What is the tension in the rope if the monkey climbs down with an acceleration of 4 ms−2a)200 Nb)300 Nc)240 Nd)280 NCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. What is the tension in the rope if the monkey climbs down with an acceleration of 4 ms−2a)200 Nb)300 Nc)240 Nd)280 NCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of A monkey of mass 40 kg climbs on a rope which can stand a maximum tension of 600 N. What is the tension in the rope if the monkey climbs down with an acceleration of 4 ms−2a)200 Nb)300 Nc)240 Nd)280 NCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
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