The wheatstone bridge shown in figure is balanced if the position of c...
The wheatstone bridge is a circuit that is used to measure an unknown electrical resistance by balancing it with known resistances. In a balanced wheatstone bridge, the galvanometer G shows zero deflection, indicating that the bridge is in equilibrium.
Interchanging the positions of cell E and galvanometer G in the wheatstone bridge will have an impact on the condition for zero deflection. Let's analyze the different options mentioned in the question:
A) Only if all resistors are equal:
If all resistors in the wheatstone bridge are equal, then the bridge will be balanced regardless of the positions of cell E and galvanometer G. This is because the ratio of the resistances in each arm of the bridge will be the same, resulting in a balanced condition.
B) Only if r1=r3 and R2=R4:
If the resistors in the wheatstone bridge are not equal, but r1=r3 and R2=R4, then the bridge can still be balanced. In this case, the ratio of the resistances in the two arms of the bridge will be the same, allowing for a balanced condition.
C) Only if r1r4=r2r3:
If the resistors in the wheatstone bridge do not satisfy the conditions mentioned in options A and B, then the bridge can only be balanced if r1r4=r2r3. This condition ensures that the product of the resistances in one arm of the bridge is equal to the product of the resistances in the other arm, leading to a balanced condition.
In summary, the answer is option C, that is, the galvanometer G will show zero deflection only if r1r4=r2r3. This condition is necessary to balance the wheatstone bridge when the positions of cell E and galvanometer G are interchanged.
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.