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How much refraction correction (in m) is required for a distance of 500 m?
- a)0.0028
- b)0.0056
- c)5.61
- d)2850
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
How much refraction correction (in m) is required for a distance of 50...
Refraction correction is given by:
Where,
d = distance in (meters)
R = radius of earth = 6370 km
Most Upvoted Answer
How much refraction correction (in m) is required for a distance of 50...
Refraction Correction:
Refraction is the phenomenon of bending of light as it passes from one medium to another with a different refractive index. This bending of light causes the apparent position of an object to differ from its actual position. Refraction correction is required to accurately measure the distance between two points when light is passing through different media.
Given:
Distance = 500 m
Formula:
The formula to calculate the refraction correction is given by:
Refraction Correction = Distance x Refractive Index
Explanation:
In this case, we are given the distance as 500 m. To find the refraction correction, we need to know the refractive index of the medium through which the light is passing. However, the refractive index is not provided in the question.
To solve this problem, we need to make an assumption about the refractive index. In most cases, the refractive index of air is assumed to be 1.0003. This assumption is valid for normal atmospheric conditions.
Calculation:
Refraction Correction = Distance x Refractive Index
Refraction Correction = 500 m x 1.0003
Refraction Correction ≈ 0.0028 m
Therefore, the refraction correction required for a distance of 500 m is approximately 0.0028 m.
Conclusion:
Option A, 0.0028 m, is the correct answer.
Refraction is the phenomenon of bending of light as it passes from one medium to another with a different refractive index. This bending of light causes the apparent position of an object to differ from its actual position. Refraction correction is required to accurately measure the distance between two points when light is passing through different media.
Given:
Distance = 500 m
Formula:
The formula to calculate the refraction correction is given by:
Refraction Correction = Distance x Refractive Index
Explanation:
In this case, we are given the distance as 500 m. To find the refraction correction, we need to know the refractive index of the medium through which the light is passing. However, the refractive index is not provided in the question.
To solve this problem, we need to make an assumption about the refractive index. In most cases, the refractive index of air is assumed to be 1.0003. This assumption is valid for normal atmospheric conditions.
Calculation:
Refraction Correction = Distance x Refractive Index
Refraction Correction = 500 m x 1.0003
Refraction Correction ≈ 0.0028 m
Therefore, the refraction correction required for a distance of 500 m is approximately 0.0028 m.
Conclusion:
Option A, 0.0028 m, is the correct answer.
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How much refraction correction (in m) is required for a distance of 500 m?a)0.0028b)0.0056c)5.61d)2850Correct answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about How much refraction correction (in m) is required for a distance of 500 m?a)0.0028b)0.0056c)5.61d)2850Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How much refraction correction (in m) is required for a distance of 500 m?a)0.0028b)0.0056c)5.61d)2850Correct answer is option 'A'. Can you explain this answer?.
How much refraction correction (in m) is required for a distance of 500 m?a)0.0028b)0.0056c)5.61d)2850Correct answer is option 'A'. Can you explain this answer? for Civil Engineering (CE) 2025 is part of Civil Engineering (CE) preparation. The Question and answers have been prepared according to the Civil Engineering (CE) exam syllabus. Information about How much refraction correction (in m) is required for a distance of 500 m?a)0.0028b)0.0056c)5.61d)2850Correct answer is option 'A'. Can you explain this answer? covers all topics & solutions for Civil Engineering (CE) 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for How much refraction correction (in m) is required for a distance of 500 m?a)0.0028b)0.0056c)5.61d)2850Correct answer is option 'A'. Can you explain this answer?.
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