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Choose the incorrect statement with respect to the use of FD in half-wave circuits.
- a)Input pf is improved
- b)Load current waveform is improved
- c)It prevents the load voltage from becoming negative
- d)Reduces the reverse voltage (PIV) faced by the SCR
Correct answer is option 'D'. Can you explain this answer?
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Choose the incorrect statement with respect to the use of FD in half-w...
PIV is unaffected with the use of FD (freewheeling diodes).
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Choose the incorrect statement with respect to the use of FD in half-w...
Incorrect Statement: Reduces the reverse voltage (PIV) faced by the SCR
Explanation:
To understand why option D is incorrect, let's first understand the concept of forward voltage drop (FD) in half-wave circuits and its impact on various parameters.
1. Forward Voltage Drop (FD):
In a half-wave rectifier circuit, a diode is used to convert alternating current (AC) into direct current (DC). The diode has a forward voltage drop (FD) associated with it, which is the voltage across the diode when it is forward-biased and conducting current. This forward voltage drop depends on the type of diode used.
2. Impact on Parameters:
a) Input Power Factor (PF):
The forward voltage drop (FD) in a diode causes a phase shift between the input voltage and current. This phase shift leads to a lower input power factor. However, the FD does not improve the power factor; it actually degrades it. Therefore, option A is incorrect.
b) Load Current Waveform:
The FD in a diode causes a voltage drop across it, resulting in a non-linear load current waveform. This waveform is characterized by a short conduction time during the positive half-cycle of the input voltage. As a result, the load current waveform is not improved but rather distorted. Therefore, option B is incorrect.
c) Preventing Load Voltage from Becoming Negative:
During the negative half-cycle of the input voltage, the diode is reverse-biased and does not conduct current. This prevents the load voltage from becoming negative and ensures that only the positive half-cycle of the input voltage is rectified. Therefore, option C is correct.
d) Reverse Voltage (PIV) Faced by the SCR:
The reverse voltage (Peak Inverse Voltage or PIV) faced by the silicon-controlled rectifier (SCR) is determined by the peak voltage of the input waveform. The FD in the diode does not affect the reverse voltage faced by the SCR. Therefore, option D is incorrect.
Conclusion:
The correct statement with respect to the use of FD in half-wave circuits is that it prevents the load voltage from becoming negative. The other statements provided in the options are either incorrect or unrelated to the FD in half-wave circuits.
Explanation:
To understand why option D is incorrect, let's first understand the concept of forward voltage drop (FD) in half-wave circuits and its impact on various parameters.
1. Forward Voltage Drop (FD):
In a half-wave rectifier circuit, a diode is used to convert alternating current (AC) into direct current (DC). The diode has a forward voltage drop (FD) associated with it, which is the voltage across the diode when it is forward-biased and conducting current. This forward voltage drop depends on the type of diode used.
2. Impact on Parameters:
a) Input Power Factor (PF):
The forward voltage drop (FD) in a diode causes a phase shift between the input voltage and current. This phase shift leads to a lower input power factor. However, the FD does not improve the power factor; it actually degrades it. Therefore, option A is incorrect.
b) Load Current Waveform:
The FD in a diode causes a voltage drop across it, resulting in a non-linear load current waveform. This waveform is characterized by a short conduction time during the positive half-cycle of the input voltage. As a result, the load current waveform is not improved but rather distorted. Therefore, option B is incorrect.
c) Preventing Load Voltage from Becoming Negative:
During the negative half-cycle of the input voltage, the diode is reverse-biased and does not conduct current. This prevents the load voltage from becoming negative and ensures that only the positive half-cycle of the input voltage is rectified. Therefore, option C is correct.
d) Reverse Voltage (PIV) Faced by the SCR:
The reverse voltage (Peak Inverse Voltage or PIV) faced by the silicon-controlled rectifier (SCR) is determined by the peak voltage of the input waveform. The FD in the diode does not affect the reverse voltage faced by the SCR. Therefore, option D is incorrect.
Conclusion:
The correct statement with respect to the use of FD in half-wave circuits is that it prevents the load voltage from becoming negative. The other statements provided in the options are either incorrect or unrelated to the FD in half-wave circuits.
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Choose the incorrect statement with respect to the use of FD in half-wave circuits.a)Input pf is improvedb)Load current waveform is improvedc)It prevents the load voltage from becoming negatived)Reduces the reverse voltage (PIV) faced by the SCRCorrect answer is option 'D'. Can you explain this answer?
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