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A telescope has an objective lens of 10 cmdiameter and is situated at a distance of onekilometer from two objects. The minimumdistance between these two objects, which canbe resolved by the telescope, when the meanwavelength of light is 5000 Å, is of the order of             [2004]
  • a)
    5 cm
  • b)
    0.5 m
  • c)
    5 m
  • d)
    5 mm
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A telescope has an objective lens of 10 cmdiameter and is situated at ...
or, x = 1.22 × 5 × 10–3 m = 6.1 mm
∴ x is of the order of 5 mm.
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A telescope has an objective lens of 10 cmdiameter and is situated at ...
Angstroms, can be calculated using the Rayleigh criterion:

θ = 1.22 λ/D

where θ is the angular resolution, λ is the wavelength of light, and D is the diameter of the objective lens.

In this case, we have:

D = 10 cm = 0.1 m
λ = 5000 angstroms = 500 nm = 5 × 10^-7 m

So, the angular resolution is:

θ = 1.22 × 5 × 10^-7 / 0.1
θ = 6.1 × 10^-9 radians

To find the minimum distance that can be resolved, we need to use the small angle approximation:

θ ≈ d / D

where d is the distance between the two objects and D is the distance from the telescope to the objects.

In this case, we have:

D = 1 km = 10^3 m

So, the minimum distance that can be resolved is:

d = θ × D
d = 6.1 × 10^-9 × 10^3
d = 6.1 × 10^-6 m

Therefore, the minimum distance that can be resolved by the telescope is 6.1 micrometers.
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A telescope has an objective lens of 10 cmdiameter and is situated at a distance of onekilometer from two objects. The minimumdistance between these two objects, which canbe resolved by the telescope, when the meanwavelength of light is 5000 Å, is of the order of [2004]a)5 cmb)0.5 mc)5 md)5 mmCorrect answer is option 'D'. Can you explain this answer?
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